Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 3)
3.
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
Discussion:
42 comments Page 3 of 5.
Deepak kumar said:
5 years ago
Th/Ts=(D^4-d^4)/D*Ds^3,
Ds is diameter of solid shaft,
put d=D/2,
we get 15/16,
Ds is diameter of solid shaft,
put d=D/2,
we get 15/16,
Prachi said:
6 years ago
Yes, it is 16/15 because it has asked for the ratio of solid to the hollow shaft.
(1)
Tamene malke said:
3 years ago
It is very good for all engineering students, thanks to everyone for explaining.
(3)
BOSS said:
4 years ago
Therefore the torsion = th/ts.
Th=15, ts=16.
Hence, torsion (t) =th/ts=15/16.
Th=15, ts=16.
Hence, torsion (t) =th/ts=15/16.
(3)
Pratyush said:
5 years ago
Here torsion of solid shaft/torsion of the hollow shaft.
Ts/Th =16/15.
Ts/Th =16/15.
(2)
Bharat said:
1 decade ago
Zp(solid)/Zp(hollow) = (pi*D^3/16)/(pi*(D^4-(D/2)^4)/16D) = 16/15.
Azzu said:
7 years ago
Strength proportional to section modulus,
So, I got 16/15.
So, I got 16/15.
Ajeet said:
1 decade ago
What is diameter of sun and internal and external heat?
MAHARAJ said:
8 years ago
@Bhagchand.
Yes, you are right.
The answer is 16/15.
Yes, you are right.
The answer is 16/15.
Abidha karthu said:
6 years ago
Yes, the ratio of solid to hollow will be 16/15.
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