Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 3)
3.
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
Discussion:
42 comments Page 2 of 5.
Maggie said:
1 decade ago
The strength of a solid shaft in torsion is given by,
T(solid shaft) = (pi/16)*(max stres)*(D^3).
T(hollow shaft) = (pi/16)*(max stres)*(D^4-d^4)/D.
On solving we get 15/16.
T(solid shaft) = (pi/16)*(max stres)*(D^3).
T(hollow shaft) = (pi/16)*(max stres)*(D^4-d^4)/D.
On solving we get 15/16.
Ravikumar said:
8 years ago
The solid section max shear stress is 16T/pi D3.
Hollow section is 16T/piD^3*[1-[D^4/d^4]].
The ratio of these to is 15/16 once remembering d=D/2.
Hollow section is 16T/piD^3*[1-[D^4/d^4]].
The ratio of these to is 15/16 once remembering d=D/2.
Ekon said:
7 years ago
Answer should be 16/15. If the answer is 15/16 then it is implying that the hollow shaft is stronger than the solid shaft of same outer diameter, which is not correct.
Virendra said:
1 decade ago
Ratio will be 16/15.
Simply if equal outer diameter then solid shaft will be more strong. But if material are same then hollow shaft will be more strong.
Simply if equal outer diameter then solid shaft will be more strong. But if material are same then hollow shaft will be more strong.
Murli meena said:
1 decade ago
Dia of solid shaft = D.
DIA OF HOLLOW SHAFT = d/2.
The ratio of solid shaft = 16.
The ratio of hollow shaft = 15.
Total tension in shafts = 15/16.
DIA OF HOLLOW SHAFT = d/2.
The ratio of solid shaft = 16.
The ratio of hollow shaft = 15.
Total tension in shafts = 15/16.
ABDUL SOVAN KHAN said:
8 years ago
((π/16)*maximum shere stress*(outside dia)^3)/((π/16)*maximum shere stress*((out side dia^4-inside dia^4)/inside dia)=16D^4/15D^4=16/15.
Parth said:
5 years ago
@All.
The question is ratio of the solid shaft to the hollow shaft not hollow shaft to solid shaft.
So the answer will be : 16/15.
The question is ratio of the solid shaft to the hollow shaft not hollow shaft to solid shaft.
So the answer will be : 16/15.
(3)
Vamsiambati said:
4 years ago
(T hollow/T shaft)=(D^4-d^4)/D^4.
Here D= Diameter of Solid Shaft.
d=Diameter of Hollow Shaft = D/2.
(D^4-(D/2)^4)/D^4 =15/16.
Here D= Diameter of Solid Shaft.
d=Diameter of Hollow Shaft = D/2.
(D^4-(D/2)^4)/D^4 =15/16.
(8)
Parna sengupta said:
1 decade ago
For a hollow shaft whose external diameter is d and internal diameter is d/2, then what will be the polar modulus?
Bhagchand Golhani said:
8 years ago
Zp= π/32(d^4).
So,
Zp(s)/Zp(h)=[π/32d^4]/[π/32*(15d^4)/16],
=16/15.
So,
Zp(s)/Zp(h)=[π/32d^4]/[π/32*(15d^4)/16],
=16/15.
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