Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 1)
1.
A rectangular bar of width b and height h is being used as a cantilever. The loading is in a plane parallel to the side b. The section modulus is
Discussion:
45 comments Page 1 of 5.
Jeldi said:
8 years ago
In general terms b= width and d or h = depth or height respectively. When loading is applied we consider bd^3/12 (hear loading is parallel to depth) and y=d/2.
Hear in this problem,
Parallel to width is asked making it shifting terms from width as depth (assume that u have rotated your beam)
So hear instead of bd^3 /12 and y=d/2.
V get db^3/12 and y= b/2.
Making Z=I/Y as db^2/6.
Hear in this problem,
Parallel to width is asked making it shifting terms from width as depth (assume that u have rotated your beam)
So hear instead of bd^3 /12 and y=d/2.
V get db^3/12 and y= b/2.
Making Z=I/Y as db^2/6.
(2)
RIYAS said:
8 years ago
Section modulus is the ratio of MOI of N.A & Distance from NA from the extreme stressed fibre.
Here NA plays the main role. The load applied in the face of Length x depth. This face elongated & opposite face compressed. So, NA will lie in between this. That means NA will pass perpendicular to width. so MOI will be b^3.d/12.
Distance from n.a. to extreme stressed fibre is b/2.
Here NA plays the main role. The load applied in the face of Length x depth. This face elongated & opposite face compressed. So, NA will lie in between this. That means NA will pass perpendicular to width. so MOI will be b^3.d/12.
Distance from n.a. to extreme stressed fibre is b/2.
(1)
Mushtaq Ahmad said:
3 years ago
This question clears out an important concept.
Definition of beam= "a structure member on which load act transversely (i.e perpendicular to N.A)."
Now in question, he said load is parallel to width means that he rotated the beam and now N.A change (because the load will act perpendicular to N.A in the beam).
Definition of beam= "a structure member on which load act transversely (i.e perpendicular to N.A)."
Now in question, he said load is parallel to width means that he rotated the beam and now N.A change (because the load will act perpendicular to N.A in the beam).
(15)
C.mallireddy said:
1 decade ago
Section modulus = I/Y (this is max).
Moment of inertia (I) = (d*b^3)/12.
= (h*b^3)/12.
In this problem width = b.
Depth d = h.
And y = b/2.
:- Z= ( (h*b^3)/12)/(b/2).
Z = (h*b^2)/6.
Moment of inertia (I) = (d*b^3)/12.
= (h*b^3)/12.
In this problem width = b.
Depth d = h.
And y = b/2.
:- Z= ( (h*b^3)/12)/(b/2).
Z = (h*b^2)/6.
Loki said:
7 years ago
Loading is parallel to side b then neural axis is perpendicular to side b, I about n.a ( n.a is the axis parallel to bending direction by right-hand thumb rule ) when the plane of loading is symmetry.
GYAN PRAKASH TIWARI said:
1 decade ago
If b is width and h is height then section of modulus.
z = I/Y ; I = hb^3/12 and y = b/2 then.
z = (hb^3/12)/(b/2).
Then z = (b^2/6) is answer. Because the load is in a plane to the side b.
z = I/Y ; I = hb^3/12 and y = b/2 then.
z = (hb^3/12)/(b/2).
Then z = (b^2/6) is answer. Because the load is in a plane to the side b.
Rehan rufead said:
9 years ago
Section modulus for the rectangular section is 1/6 bd^2. ie I/y.
I = bd^3/12.
Y = d/2 bd^2/6.
Then, how the answer is option C.
I = bd^3/12.
Y = d/2 bd^2/6.
Then, how the answer is option C.
Akshay malviya said:
6 years ago
Here in the question, it is written that load is in the "plane parallel to side b". Neutral axis should be parallel to b and the correct answer should be option B.
Jothi said:
5 years ago
Section Modulus Z=I/ymax in general I= bd3/12 in this problem d=b ,b=h.
The loading is in a plane parallel to the side b. ymax= b/2, Z= hb3/12/b/2 =b2h/6.
The loading is in a plane parallel to the side b. ymax= b/2, Z= hb3/12/b/2 =b2h/6.
(29)
Bittu Gurrala said:
3 months ago
@All.
Always remember the cube in the Moment of Inertia has to go to the perpendicular side that is h here and Z = I/ (h/2).
That gives (b*h^2)/6.
Always remember the cube in the Moment of Inertia has to go to the perpendicular side that is h here and Z = I/ (h/2).
That gives (b*h^2)/6.
(3)
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