Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 1)
1.
A rectangular bar of width b and height h is being used as a cantilever. The loading is in a plane parallel to the side b. The section modulus is
none of these.
Discussion:
45 comments Page 1 of 5.
Jothi said:
5 years ago
Section Modulus Z=I/ymax in general I= bd3/12 in this problem d=b ,b=h.
The loading is in a plane parallel to the side b. ymax= b/2, Z= hb3/12/b/2 =b2h/6.
The loading is in a plane parallel to the side b. ymax= b/2, Z= hb3/12/b/2 =b2h/6.
(29)
Mushtaq Ahmad said:
3 years ago
This question clears out an important concept.
Definition of beam= "a structure member on which load act transversely (i.e perpendicular to N.A)."
Now in question, he said load is parallel to width means that he rotated the beam and now N.A change (because the load will act perpendicular to N.A in the beam).
Definition of beam= "a structure member on which load act transversely (i.e perpendicular to N.A)."
Now in question, he said load is parallel to width means that he rotated the beam and now N.A change (because the load will act perpendicular to N.A in the beam).
(15)
Sshashi said:
3 years ago
Z = I/Y.
= bh^2/12 ÷ h/2,
= bh^2/6.
So, the answer is B.
= bh^2/12 ÷ h/2,
= bh^2/6.
So, the answer is B.
(6)
Yogal said:
1 year ago
C is correct.
Here the load acts on the depth side.
So, the answer is b^2h/6.
Here the load acts on the depth side.
So, the answer is b^2h/6.
(4)
Bittu Gurrala said:
3 months ago
@All.
Always remember the cube in the Moment of Inertia has to go to the perpendicular side that is h here and Z = I/ (h/2).
That gives (b*h^2)/6.
Always remember the cube in the Moment of Inertia has to go to the perpendicular side that is h here and Z = I/ (h/2).
That gives (b*h^2)/6.
(3)
Rakesh said:
2 years ago
Option B is correct.
(2)
Pradeep karsh said:
6 years ago
Thaks to all.
(2)
Jeldi said:
8 years ago
In general terms b= width and d or h = depth or height respectively. When loading is applied we consider bd^3/12 (hear loading is parallel to depth) and y=d/2.
Hear in this problem,
Parallel to width is asked making it shifting terms from width as depth (assume that u have rotated your beam)
So hear instead of bd^3 /12 and y=d/2.
V get db^3/12 and y= b/2.
Making Z=I/Y as db^2/6.
Hear in this problem,
Parallel to width is asked making it shifting terms from width as depth (assume that u have rotated your beam)
So hear instead of bd^3 /12 and y=d/2.
V get db^3/12 and y= b/2.
Making Z=I/Y as db^2/6.
(2)
RIYAS said:
8 years ago
Section modulus is the ratio of MOI of N.A & Distance from NA from the extreme stressed fibre.
Here NA plays the main role. The load applied in the face of Length x depth. This face elongated & opposite face compressed. So, NA will lie in between this. That means NA will pass perpendicular to width. so MOI will be b^3.d/12.
Distance from n.a. to extreme stressed fibre is b/2.
Here NA plays the main role. The load applied in the face of Length x depth. This face elongated & opposite face compressed. So, NA will lie in between this. That means NA will pass perpendicular to width. so MOI will be b^3.d/12.
Distance from n.a. to extreme stressed fibre is b/2.
(1)
Santanu said:
3 years ago
Thanks @Josh.
(1)
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