Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 1)
1.
A rectangular bar of width b and height h is being used as a cantilever. The loading is in a plane parallel to the side b. The section modulus is
Discussion:
45 comments Page 2 of 5.
Venkatesh said:
5 years ago
Option B is the correct answer.
(1)
Sai chandu said:
5 years ago
@Mukesh Yada.
Please explain How y=b/2?
Please explain How y=b/2?
(1)
B.Singh said:
3 years ago
You are right, Thanks @Jothi.
ELIAS said:
6 years ago
Thank all.
Akshay malviya said:
6 years ago
Here in the question, it is written that load is in the "plane parallel to side b". Neutral axis should be parallel to b and the correct answer should be option B.
Ooha said:
1 decade ago
We are using different methods but same concept. So your process is correct no comment.
GYAN PRAKASH TIWARI said:
1 decade ago
If b is width and h is height then section of modulus.
z = I/Y ; I = hb^3/12 and y = b/2 then.
z = (hb^3/12)/(b/2).
Then z = (b^2/6) is answer. Because the load is in a plane to the side b.
z = I/Y ; I = hb^3/12 and y = b/2 then.
z = (hb^3/12)/(b/2).
Then z = (b^2/6) is answer. Because the load is in a plane to the side b.
Anantharami Reddy said:
5 years ago
Option B is correct.
Rima said:
1 decade ago
Section modulus = I/Ymax.
Here I = h*b^3/12.
And Ymax = b/2, then section modulus= (h*b^3/12)/(b/2) = h*b^2/6.
Here I = h*b^3/12.
And Ymax = b/2, then section modulus= (h*b^3/12)/(b/2) = h*b^2/6.
Ithi said:
1 decade ago
(hb^3)% (0.5b) = (hb^2%6).
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