Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 1)
1.
A rectangular bar of width b and height h is being used as a cantilever. The loading is in a plane parallel to the side b. The section modulus is
none of these.
Discussion:
45 comments Page 2 of 5.
Deepak Singh said:
1 decade ago
We know,
Z = I/Y [where, y=y(max)].
But, I = db^3/12.
y = b/2.
Now, Z = 2db^3/12d,
= db^2/6 [A/C to question d=h],
Z = hb^2/6.
Z = I/Y [where, y=y(max)].
But, I = db^3/12.
y = b/2.
Now, Z = 2db^3/12d,
= db^2/6 [A/C to question d=h],
Z = hb^2/6.
Mahesh said:
1 decade ago
Section modulus = I/y(max).
Here the load is parallel to the width b so,
I = (b^3*h)/12.
And y = b/2.
Then z = (b^2*h)/6.
Here the load is parallel to the width b so,
I = (b^3*h)/12.
And y = b/2.
Then z = (b^2*h)/6.
Prem kumar meena said:
1 decade ago
Z = I/Y(max.) I = bd^3/12 ;
y(max.) = d/2 load is parallel to side b then b=h and d=b ;
Z = hb^3/12/b/2 ;
Z = hb^2/6.
y(max.) = d/2 load is parallel to side b then b=h and d=b ;
Z = hb^3/12/b/2 ;
Z = hb^2/6.
Satyendra said:
9 years ago
Section modulus is a geometric property for a given cross-section used in the design of beams or flexural members.
Rima said:
1 decade ago
Section modulus = I/Ymax.
Here I = h*b^3/12.
And Ymax = b/2, then section modulus= (h*b^3/12)/(b/2) = h*b^2/6.
Here I = h*b^3/12.
And Ymax = b/2, then section modulus= (h*b^3/12)/(b/2) = h*b^2/6.
GHANSHYAM said:
9 years ago
Please explain that what is y and how y = b/2?
And how calculation is z = {(h*b^3/12)/(b/2).
And how calculation is z = {(h*b^3/12)/(b/2).
Devendranaik said:
9 years ago
Section modules (z) =I/Y.
MOMENT OF INERTIA (I) =B^3h/12.
Y = b/2.
Therefore = Z = I/Y = B^2h/6.
MOMENT OF INERTIA (I) =B^3h/12.
Y = b/2.
Therefore = Z = I/Y = B^2h/6.
Ooha said:
1 decade ago
We are using different methods but same concept. So your process is correct no comment.
Mukesh yadav said:
1 decade ago
Section modulus = I/Y(max).
Then I = (b^3*h)/12.
And y = b/2.
Then z = (b^2*h)/6.
Then I = (b^3*h)/12.
And y = b/2.
Then z = (b^2*h)/6.
Aftershock said:
9 years ago
It says parallel to the plan b, that means.
I = bh^3/12.
y = b/2,
Hence Z= b^2h/6.
I = bh^3/12.
y = b/2,
Hence Z= b^2h/6.
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