# Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 35)
35.
If a rectangular beam measuring 10 x 18 x 400 cm carries a unformly distributed load such that the bending stress developed is 100 kg/cm2. The intensity of the load per metre length, is
240 kg
250 kg
260 kg
270 kg
280 kg.
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 1 of 2.

George Zac said:   9 years ago
The correct answer is 270 kg.

Bending Stress = f = M/Z (Moment / section Modulus).

100 kg/cm2 = (WL^2/8)/(1/6 bd^3) M = 100/6 x 10 x 18^2.

M = 54,000 Kg.cm - 540 Kg.m.

M = WL^2/8= 540.

W = 8 * M / L^2.

W = 8 * 540 / 4^2.

W = 270 Kg.
(1)

Tanmoy Ghosh said:   2 years ago
WL^2/8.
Z = I/Y.
Z called section modulus.
F = M/Z.
Z =(BD^2/6)=540.
M = WL^2/8,
(WL^2/8)/(10*18^2/6).
W = 540 * 8/4^2,
W = 270KG,
W = 540 * 8.
(1)

Krishna said:   7 years ago
F= My/I.
M = (WL^2) /8.
M = fI/y = wl^2/8.
I = bh^3/12.
Y = h/2.

F and l are known, then we get,

W= 270 kg.

Deepak said:   5 years ago
Why you takes length in meters? All dimension take into cm than the answer is different.

Ranjit said:   6 years ago
But the type of beam is not given here then how can we use simply supported condition?

Shahsi Ranjan said:   5 years ago
Every time, assume SSB if there is not any information about support.

Sai madhav said:   6 years ago
In question there is no information about beam type.

John parker said:   8 years ago
Correct option is (D) , 270 Kg.

Bibek said:   5 years ago
D. 270 is the answer I think.

SHUBHAM said:   4 years ago
270 kg is the correct answer.