# Civil Engineering - Strength of Materials - Discussion

### Discussion :: Strength of Materials - Section 1 (Q.No.35)

35.

If a rectangular beam measuring 10 x 18 x 400 cm carries a unformly distributed load such that the bending stress developed is 100 kg/cm2. The intensity of the load per metre length, is

 [A]. 240 kg [B]. 250 kg [C]. 260 kg [D]. 270 kg [E]. 280 kg.

Explanation:

No answer description available for this question.

 George Zac said: (Feb 27, 2014) The correct answer is 270 kg. Bending Stress = f = M/Z (Moment / section Modulus). 100 kg/cm2 = (WL^2/8)/(1/6 bd^3) M = 100/6 x 10 x 18^2. M = 54,000 Kg.cm - 540 Kg.m. M = WL^2/8= 540. W = 8 * M / L^2. W = 8 * 540 / 4^2. W = 270 Kg.

 John Parker said: (Sep 25, 2015) Correct option is (D) , 270 Kg.

 Krishna said: (May 12, 2016) F= My/I. M = (WL^2) /8. M = fI/y = wl^2/8. I = bh^3/12. Y = h/2. F and l are known, then we get, W= 270 kg.

 Ranjit said: (Dec 17, 2016) But the type of beam is not given here then how can we use simply supported condition?

 Sai Madhav said: (Sep 24, 2017) In question there is no information about beam type.

 Shahsi Ranjan said: (Nov 15, 2017) Every time, assume SSB if there is not any information about support.

 Bibek said: (Mar 10, 2018) D. 270 is the answer I think.

 Satish said: (Mar 17, 2018) W=270 is right.

 Deepak said: (Jul 5, 2018) Why you takes length in meters? All dimension take into cm than the answer is different.

 Rahul said: (Aug 24, 2019) Thanks for the answer.

 Shubham said: (Sep 14, 2019) 270 kg is the correct answer.

 Tanmoy Ghosh said: (Jan 3, 2021) WL^2/8. Z = I/Y. Z called section modulus. F = M/Z. Z =(BD^2/6)=540. M = WL^2/8, (WL^2/8)/(10*18^2/6). W = 540 * 8/4^2, W = 270KG, W = 540 * 8.