Discussion :: Strength of Materials - Section 1 (Q.No.35)
|George Zac said: (Feb 27, 2014)|
|The correct answer is 270 kg.
Bending Stress = f = M/Z (Moment / section Modulus).
100 kg/cm2 = (WL^2/8)/(1/6 bd^3) M = 100/6 x 10 x 18^2.
M = 54,000 Kg.cm - 540 Kg.m.
M = WL^2/8= 540.
W = 8 * M / L^2.
W = 8 * 540 / 4^2.
W = 270 Kg.
|John Parker said: (Sep 25, 2015)|
|Correct option is (D) , 270 Kg.|
|Krishna said: (May 12, 2016)|
M = (WL^2) /8.
M = fI/y = wl^2/8.
I = bh^3/12.
Y = h/2.
F and l are known, then we get,
W= 270 kg.
|Ranjit said: (Dec 17, 2016)|
|But the type of beam is not given here then how can we use simply supported condition?|
|Sai Madhav said: (Sep 24, 2017)|
|In question there is no information about beam type.|
|Shahsi Ranjan said: (Nov 15, 2017)|
|Every time, assume SSB if there is not any information about support.|
|Bibek said: (Mar 10, 2018)|
|D. 270 is the answer I think.|
|Satish said: (Mar 17, 2018)|
|W=270 is right.|
|Deepak said: (Jul 5, 2018)|
|Why you takes length in meters? All dimension take into cm than the answer is different.|
|Rahul said: (Aug 24, 2019)|
|Thanks for the answer.|
|Shubham said: (Sep 14, 2019)|
|270 kg is the correct answer.|
|Tanmoy Ghosh said: (Jan 3, 2021)|
Z = I/Y.
Z called section modulus.
F = M/Z.
M = WL^2/8,
W = 540 * 8/4^2,
W = 270KG,
W = 540 * 8.
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