Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 2)
2.
If a circular beam of diameter d experiences a longitudinal strain 
and a lateral strain 
the volumetric strain is
and a lateral strain the volumetric strain is
none of these.
Discussion:
13 comments Page 1 of 2.
Siddhant said:
7 years ago
As lateral strain is negative (not given in the question, but obviously) volumetric strain is the sum of strain in all three directions and given lateral strain is for y and z directions. So the answer is;
P/E +2*(-lateral stain) = p/E+4p/mE.
P/E +2*(-lateral stain) = p/E+4p/mE.
(1)
Hemendra Meena said:
5 years ago
In the circular section,
ev = e1 + ed.
ev= P/E + 2P/mE.
So the answer is option A.
ev = e1 + ed.
ev= P/E + 2P/mE.
So the answer is option A.
(1)
Krishna said:
9 years ago
ev = 2ed + el, where e = strain. Then, how can we get above answer?
Ana said:
9 years ago
Can anyone explain it?
Neel said:
9 years ago
I think option A is correct.
You are right @Krisna.
You are right @Krisna.
Ankit said:
8 years ago
B is correct because the lateral stain will be negative or volumetric strain is summation of all 2or 3 direction strain.
Latha said:
8 years ago
I think the answer is A.
Roy said:
8 years ago
Yes, p/E (1-2u).
Ankush said:
8 years ago
E=3k(1-2/m),
k=bulk modulus= P/(dv/v).
k=bulk modulus= P/(dv/v).
Suryashekhar vicky said:
7 years ago
We know that;
Volumetric strain= strain in x+strain in y+ strain in z.
So,
v=p/E+(-2P/mE) +0.
Volumetric strain= strain in x+strain in y+ strain in z.
So,
v=p/E+(-2P/mE) +0.
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