Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 2)
2.
If a circular beam of diameter d experiences a longitudinal strain
and a lateral strain
the volumetric strain is


Discussion:
13 comments Page 1 of 2.
DIVAKAR M said:
4 years ago
Volumetric strain= strain in x+strain in y+ strain in z.
So,
v=p/E+(-2P/mE) +0.
V = P/E -(2P/ME).
So,
v=p/E+(-2P/mE) +0.
V = P/E -(2P/ME).
Hemendra Meena said:
5 years ago
In the circular section,
ev = e1 + ed.
ev= P/E + 2P/mE.
So the answer is option A.
ev = e1 + ed.
ev= P/E + 2P/mE.
So the answer is option A.
(1)
Ravi said:
5 years ago
In X = P/A
In y + in z = 2p/mE
so the answer is option B.
In y + in z = 2p/mE
so the answer is option B.
Dhruba said:
6 years ago
Here,
X dir. = P/E.
Y dir. = - 2P/ mE,
Z dir. = 0,
Volumetric strain= X+Y+Z.
So, ans is option B.
X dir. = P/E.
Y dir. = - 2P/ mE,
Z dir. = 0,
Volumetric strain= X+Y+Z.
So, ans is option B.
Siddhant said:
7 years ago
As lateral strain is negative (not given in the question, but obviously) volumetric strain is the sum of strain in all three directions and given lateral strain is for y and z directions. So the answer is;
P/E +2*(-lateral stain) = p/E+4p/mE.
P/E +2*(-lateral stain) = p/E+4p/mE.
(1)
Suryashekhar vicky said:
7 years ago
We know that;
Volumetric strain= strain in x+strain in y+ strain in z.
So,
v=p/E+(-2P/mE) +0.
Volumetric strain= strain in x+strain in y+ strain in z.
So,
v=p/E+(-2P/mE) +0.
Ankush said:
8 years ago
E=3k(1-2/m),
k=bulk modulus= P/(dv/v).
k=bulk modulus= P/(dv/v).
Roy said:
8 years ago
Yes, p/E (1-2u).
Latha said:
8 years ago
I think the answer is A.
Ankit said:
8 years ago
B is correct because the lateral stain will be negative or volumetric strain is summation of all 2or 3 direction strain.
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