Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 24)
24.
If n is the ratio of internal and external diameters of a hollow shaft, the ratio of the weight of the hollow shaft and that of solid shaft of same strength, will be
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 2 of 2.

Shankar said:   7 years ago
The strength of shaft means max. torque or max power transmitted capacity.
Here asking their strength equal means weight ratio of the shaft.

So weight depends on the size of the shaft.
We taking maximum torque equation of finding dia of the shaft.
Consider d for outer dia of hollow shaft and nd for inner dia of the shaft.
Then formula = (π) * [ d^4 - (nd)^4] * shear stress /16/d^4.

Assume dia of solid shaft D.

Then we equating torque of solid shaft = torque of the hollow shaft
we get D = { [d^4 - (nd)^4 ]/ d^4 }
The weight depends on the area of the shaft section so,
Hollow shaft cross-section area / solid shaft cross-section area.

By substituting the value of solid shaft dia in area formula we get the final answer.

U.S.lakshmi said:   6 years ago
I am going to prepare with this help after second carrying after two years so please explain with notations and clearly.

Manvitha said:   6 years ago
Thank you @Krishna.

Anvesh said:   5 years ago
Thank you @Krishna.

Vivek said:   4 years ago
Thank you @Krishna.


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