Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 24)
24.
If n is the ratio of internal and external diameters of a hollow shaft, the ratio of the weight of the hollow shaft and that of solid shaft of same strength, will be
Discussion:
15 comments Page 2 of 2.
LATHA said:
8 years ago
Please expain clearly.
Tailam mahesh said:
8 years ago
I can't understand. Can anyone explain clearly?
Ram Krishna Adhikari said:
9 years ago
Now, d = nD, D = d/n.
Ratio of the weight = ratio of C/A = (d^2 * (1/n^2-1))/D^2 ...1.
Find d^/D^2 as follows:
((d/n)^3 - d^3)/D^3 = Th/Ts = 1
(d/D)^2 = (1-n^2)/(1-n^4)^(2/3).
Substitute in eq 1 you will get the answer.
Ratio of the weight = ratio of C/A = (d^2 * (1/n^2-1))/D^2 ...1.
Find d^/D^2 as follows:
((d/n)^3 - d^3)/D^3 = Th/Ts = 1
(d/D)^2 = (1-n^2)/(1-n^4)^(2/3).
Substitute in eq 1 you will get the answer.
Dalisha said:
9 years ago
Given, d/D = n and stress ratio D^4 - d^4/D^4 = Th/Ts.
Now, d = nD, D = d/n putin above and get 1 - n^2/(1 - n^4)^2/3.
Now, d = nD, D = d/n putin above and get 1 - n^2/(1 - n^4)^2/3.
M.raja reddy(svkp cumbum) said:
9 years ago
Anyone give explanation for the answer.
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