Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 37)
37.
A shaft turning 150 r.p.m. is subjected to a torque of 150 kgm. Horse power transmitted by the shaft is
Discussion:
17 comments Page 1 of 2.
Rashid said:
5 years ago
Power = 2πNT/60 ( in watts) = 2πNT/(60*746) (in HP).
N = 150 r.p.m.
T = 150 Kgm = 150*10Nm = 1500Nm (1kg = 10N approx).
After putting all value in the equation you will get,
Ans : 10π.
N = 150 r.p.m.
T = 150 Kgm = 150*10Nm = 1500Nm (1kg = 10N approx).
After putting all value in the equation you will get,
Ans : 10π.
Nikhil said:
1 decade ago
Where N = The speed in r.p.m.
T = the torque in kgm.
Therefore,
P=2*(py)*N*T/4500.
Where (py) is 3.141.
T = the torque in kgm.
Therefore,
P=2*(py)*N*T/4500.
Where (py) is 3.141.
Sachin said:
8 years ago
@Venkat.
T is in kg-m, so convert it to Newton by multiplying 10m/s^2.
You will get 4500.
T is in kg-m, so convert it to Newton by multiplying 10m/s^2.
You will get 4500.
Venkatramana g said:
8 years ago
1HP=745.699watts then 2πN/60 x 1/745.699 gives 2πNT/45000 how 4500 comes?
Akhilandeshwari said:
9 years ago
P = 2 * φ * N * T/4500,
P = 2 * φ * 150 * 150/4500,
p = 10 *φ.
P = 2 * φ * 150 * 150/4500,
p = 10 *φ.
Bhavsingh said:
10 years ago
p = 2*(py)*n*T/4500.
T = 150 kgm.
n = 150 r.p.m.
p = 10*(py).
T = 150 kgm.
n = 150 r.p.m.
p = 10*(py).
Rakesh said:
7 years ago
2πNT/45000.
Because 1hp =746watt.
Then you will get 10π.
Because 1hp =746watt.
Then you will get 10π.
Parth said:
5 years ago
1 kg = 9.81N.
Power = angular velocity x torque x 9.81 watts.
Power = angular velocity x torque x 9.81 watts.
(4)
Koushik said:
7 years ago
Work done per second = 2πNT/60KNm.
N=RPM.
T=Torque in KNm.
N=RPM.
T=Torque in KNm.
Shiva said:
8 years ago
P = 2πNT/4500.
We get p=31.41,
Which is equal to 10π.
We get p=31.41,
Which is equal to 10π.
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