Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 37)
37.
A shaft turning 150 r.p.m. is subjected to a torque of 150 kgm. Horse power transmitted by the shaft is
Discussion:
17 comments Page 2 of 2.
Ruchir said:
7 years ago
P = 2πNT/60.
P = 2*π*150*150*10/60*746watt.
= 10π.
P = 2*π*150*150*10/60*746watt.
= 10π.
Raghuraj singh chauhan said:
8 years ago
1 horse power = 745.6998 watts, then we find the answer.
Monika said:
9 years ago
p = 2nNT/4500.
N = 150 rpm.
T = 150 kgm.
p = 10n.
N = 150 rpm.
T = 150 kgm.
p = 10n.
Krishna murti said:
8 years ago
How 4500 come? Anybody, Kindly explain it.
MJM Gcek said:
4 years ago
You Solved it clearly, Thanks @Rashid.
Tanmoy Ghosh said:
5 years ago
2π*N*T/4500,
10π.
10π.
(5)
Prasenjit said:
8 years ago
2πNT/4500.
(1)
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