Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 37)
37.
A shaft turning 150 r.p.m. is subjected to a torque of 150 kgm. Horse power transmitted by the shaft is
Discussion:
17 comments Page 1 of 2.
MJM Gcek said:
4 years ago
You Solved it clearly, Thanks @Rashid.
Tanmoy Ghosh said:
5 years ago
2π*N*T/4500,
10π.
10π.
(5)
Parth said:
5 years ago
1 kg = 9.81N.
Power = angular velocity x torque x 9.81 watts.
Power = angular velocity x torque x 9.81 watts.
(4)
Rashid said:
5 years ago
Power = 2πNT/60 ( in watts) = 2πNT/(60*746) (in HP).
N = 150 r.p.m.
T = 150 Kgm = 150*10Nm = 1500Nm (1kg = 10N approx).
After putting all value in the equation you will get,
Ans : 10π.
N = 150 r.p.m.
T = 150 Kgm = 150*10Nm = 1500Nm (1kg = 10N approx).
After putting all value in the equation you will get,
Ans : 10π.
Koushik said:
7 years ago
Work done per second = 2πNT/60KNm.
N=RPM.
T=Torque in KNm.
N=RPM.
T=Torque in KNm.
Rakesh said:
7 years ago
2πNT/45000.
Because 1hp =746watt.
Then you will get 10π.
Because 1hp =746watt.
Then you will get 10π.
Ruchir said:
7 years ago
P = 2πNT/60.
P = 2*π*150*150*10/60*746watt.
= 10π.
P = 2*π*150*150*10/60*746watt.
= 10π.
Prasenjit said:
8 years ago
2πNT/4500.
(1)
Sachin said:
8 years ago
@Venkat.
T is in kg-m, so convert it to Newton by multiplying 10m/s^2.
You will get 4500.
T is in kg-m, so convert it to Newton by multiplying 10m/s^2.
You will get 4500.
Shiva said:
8 years ago
P = 2πNT/4500.
We get p=31.41,
Which is equal to 10π.
We get p=31.41,
Which is equal to 10π.
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