# Civil Engineering - Strength of Materials - Discussion

### Discussion :: Strength of Materials - Section 1 (Q.No.37)

37.

A shaft turning 150 r.p.m. is subjected to a torque of 150 kgm. Horse power transmitted by the shaft is

 [A]. π [B]. 10 π [C]. π2 [D]. 1/π

Explanation:

No answer description available for this question.

 Nikhil said: (Nov 17, 2013) Where N = The speed in r.p.m. T = the torque in kgm. Therefore, P=2*(py)*N*T/4500. Where (py) is 3.141.

 Bhavsingh said: (Oct 26, 2015) p = 2*(py)*n*T/4500. T = 150 kgm. n = 150 r.p.m. p = 10*(py).

 Monika said: (Apr 19, 2016) p = 2nNT/4500. N = 150 rpm. T = 150 kgm. p = 10n.

 Akhilandeshwari said: (Aug 26, 2016) P = 2 * φ * N * T/4500, P = 2 * φ * 150 * 150/4500, p = 10 *φ.

 Krishna Murti said: (Mar 14, 2017) How 4500 come? Anybody, Kindly explain it.

 Raghuraj Singh Chauhan said: (Mar 16, 2017) 1 horse power = 745.6998 watts, then we find the answer.

 Venkatramana G said: (Sep 3, 2017) 1HP=745.699watts then 2πN/60 x 1/745.699 gives 2πNT/45000 how 4500 comes?

 Shiva said: (Sep 23, 2017) P = 2πNT/4500. We get p=31.41, Which is equal to 10π.

 Sachin said: (Oct 14, 2017) @Venkat. T is in kg-m, so convert it to Newton by multiplying 10m/s^2. You will get 4500.

 Prasenjit said: (Jan 2, 2018) 2πNT/4500.

 Ruchir said: (May 5, 2018) P = 2πNT/60. P = 2*π*150*150*10/60*746watt. = 10π.

 Rakesh said: (Jun 5, 2018) 2πNT/45000. Because 1hp =746watt. Then you will get 10π.

 Koushik said: (Sep 10, 2018) Work done per second = 2πNT/60KNm. N=RPM. T=Torque in KNm.

 Rashid said: (Apr 3, 2020) Power = 2πNT/60 ( in watts) = 2πNT/(60*746) (in HP). N = 150 r.p.m. T = 150 Kgm = 150*10Nm = 1500Nm (1kg = 10N approx). After putting all value in the equation you will get, Ans : 10π.

 Parth said: (Aug 5, 2020) 1 kg = 9.81N. Power = angular velocity x torque x 9.81 watts.

 Tanmoy Ghosh said: (Jan 3, 2021) 2π*N*T/4500, 10π.

 Mjm Gcek said: (Aug 17, 2021) You Solved it clearly, Thanks @Rashid.