Civil Engineering - Strength of Materials - Discussion

37. 

A shaft turning 150 r.p.m. is subjected to a torque of 150 kgm. Horse power transmitted by the shaft is

[A]. π
[B]. 10 π
[C]. π2
[D]. 1/π

Answer: Option B

Explanation:

No answer description available for this question.

Nikhil said: (Nov 17, 2013)  
Where N = The speed in r.p.m.
T = the torque in kgm.

Therefore,

P=2*(py)*N*T/4500.

Where (py) is 3.141.

Bhavsingh said: (Oct 26, 2015)  
p = 2*(py)*n*T/4500.

T = 150 kgm.

n = 150 r.p.m.

p = 10*(py).

Monika said: (Apr 19, 2016)  
p = 2nNT/4500.

N = 150 rpm.

T = 150 kgm.

p = 10n.

Akhilandeshwari said: (Aug 26, 2016)  
P = 2 * φ * N * T/4500,
P = 2 * φ * 150 * 150/4500,
p = 10 *φ.

Krishna Murti said: (Mar 14, 2017)  
How 4500 come? Anybody, Kindly explain it.

Raghuraj Singh Chauhan said: (Mar 16, 2017)  
1 horse power = 745.6998 watts, then we find the answer.

Venkatramana G said: (Sep 3, 2017)  
1HP=745.699watts then 2πN/60 x 1/745.699 gives 2πNT/45000 how 4500 comes?

Shiva said: (Sep 23, 2017)  
P = 2πNT/4500.
We get p=31.41,
Which is equal to 10π.

Sachin said: (Oct 14, 2017)  
@Venkat.

T is in kg-m, so convert it to Newton by multiplying 10m/s^2.
You will get 4500.

Prasenjit said: (Jan 2, 2018)  
2πNT/4500.

Ruchir said: (May 5, 2018)  
P = 2πNT/60.

P = 2*π*150*150*10/60*746watt.
= 10π.

Rakesh said: (Jun 5, 2018)  
2πNT/45000.
Because 1hp =746watt.
Then you will get 10π.

Koushik said: (Sep 10, 2018)  
Work done per second = 2πNT/60KNm.
N=RPM.
T=Torque in KNm.

Rashid said: (Apr 3, 2020)  
Power = 2πNT/60 ( in watts) = 2πNT/(60*746) (in HP).

N = 150 r.p.m.
T = 150 Kgm = 150*10Nm = 1500Nm (1kg = 10N approx).

After putting all value in the equation you will get,
Ans : 10π.

Parth said: (Aug 5, 2020)  
1 kg = 9.81N.

Power = angular velocity x torque x 9.81 watts.

Tanmoy Ghosh said: (Jan 3, 2021)  
2π*N*T/4500,
10π.

Mjm Gcek said: (Aug 17, 2021)  
You Solved it clearly, Thanks @Rashid.

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