Discussion :: Strength of Materials - Section 1 (Q.No.37)
A shaft turning 150 r.p.m. is subjected to a torque of 150 kgm. Horse power transmitted by the shaft is
Answer: Option B
No answer description available for this question.
|Nikhil said: (Nov 17, 2013)|
|Where N = The speed in r.p.m.
T = the torque in kgm.
Where (py) is 3.141.
|Bhavsingh said: (Oct 26, 2015)|
|p = 2*(py)*n*T/4500.
T = 150 kgm.
n = 150 r.p.m.
p = 10*(py).
|Monika said: (Apr 19, 2016)|
|p = 2nNT/4500.
N = 150 rpm.
T = 150 kgm.
p = 10n.
|Akhilandeshwari said: (Aug 26, 2016)|
|P = 2 * φ * N * T/4500,
P = 2 * φ * 150 * 150/4500,
p = 10 *φ.
|Krishna Murti said: (Mar 14, 2017)|
|How 4500 come? Anybody, Kindly explain it.|
|Raghuraj Singh Chauhan said: (Mar 16, 2017)|
|1 horse power = 745.6998 watts, then we find the answer.|
|Venkatramana G said: (Sep 3, 2017)|
|1HP=745.699watts then 2πN/60 x 1/745.699 gives 2πNT/45000 how 4500 comes?|
|Shiva said: (Sep 23, 2017)|
|P = 2πNT/4500.
We get p=31.41,
Which is equal to 10π.
|Sachin said: (Oct 14, 2017)|
T is in kg-m, so convert it to Newton by multiplying 10m/s^2.
You will get 4500.
|Prasenjit said: (Jan 2, 2018)|
|Ruchir said: (May 5, 2018)|
|P = 2πNT/60.
P = 2*π*150*150*10/60*746watt.
|Rakesh said: (Jun 5, 2018)|
Because 1hp =746watt.
Then you will get 10π.
|Koushik said: (Sep 10, 2018)|
|Work done per second = 2πNT/60KNm.
T=Torque in KNm.
|Rashid said: (Apr 3, 2020)|
|Power = 2πNT/60 ( in watts) = 2πNT/(60*746) (in HP).
N = 150 r.p.m.
T = 150 Kgm = 150*10Nm = 1500Nm (1kg = 10N approx).
After putting all value in the equation you will get,
Ans : 10π.
|Parth said: (Aug 5, 2020)|
|1 kg = 9.81N.
Power = angular velocity x torque x 9.81 watts.
|Tanmoy Ghosh said: (Jan 3, 2021)|
|Mjm Gcek said: (Aug 17, 2021)|
|You Solved it clearly, Thanks @Rashid.|
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