Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 7)
7.
A three-hinged arch is said to be :
Discussion:
15 comments Page 1 of 2.
Teja said:
1 decade ago
Why it was statically determinate structure?
Vicky said:
1 decade ago
Why option A is right?
Mayank Chetiwal said:
1 decade ago
since support reactions are 4 and equilibrium equations were 3 and because of a hinge 1 additional equilibrium will be added So,
D = R-S.
R = 4.
S = 3+1 = 4.
D = 4-4 = 0.
Statically determinate.
D = R-S.
R = 4.
S = 3+1 = 4.
D = 4-4 = 0.
Statically determinate.
Parimal Das said:
1 decade ago
We know that D = R-S.
So, support reaction is 4, equilibrium equations 3, because it is hinged.
So, D = 4-4 = 0.
It is statistical.
So, support reaction is 4, equilibrium equations 3, because it is hinged.
So, D = 4-4 = 0.
It is statistical.
Hitesh said:
10 years ago
Three hinged arc mean?
Karan said:
9 years ago
You are absolutely correct @Mayank.
Anwar Kohistani said:
8 years ago
D=R-3N where R=6 b/c of 3 hinges and N=2 two member so D=6-3*2=0.
Parameshwar said:
8 years ago
We know that D= R-3N.
Here R 6each hing reaction 2 so 3 hinged = 6.
Now mamber = 2.
so put hte value in eqution,
D=6-(3*2),
= 0.
Here R 6each hing reaction 2 so 3 hinged = 6.
Now mamber = 2.
so put hte value in eqution,
D=6-(3*2),
= 0.
(2)
Rahul Kumar singh said:
7 years ago
Since support reactions are 4 and equilibrium equations were 3 and because of a hinge 1 additional equilibrium will be added So,
D = R-S.
R = 4.
S = 3+1 = 4.
D = 4-4 = 0.
Statically determinate.
D = R-S.
R = 4.
S = 3+1 = 4.
D = 4-4 = 0.
Statically determinate.
(2)
Sujatha srinu said:
7 years ago
Why should we add additional equilibrium?
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