Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 7)
7.
A three-hinged arch is said to be :
Discussion:
15 comments Page 1 of 2.
Inayat Ullah Kakar said:
9 months ago
M+R=2j for statically determinate structure.
M+R>2j for statically indeterminate structure.
M+R< 2j for unstable structure.
Here;
M = members.
R = reaction.
J = joints.
Or
R=3n(determinate).
R>3n(indeterminate),
R<3n (unstable).
M+R>2j for statically indeterminate structure.
M+R< 2j for unstable structure.
Here;
M = members.
R = reaction.
J = joints.
Or
R=3n(determinate).
R>3n(indeterminate),
R<3n (unstable).
(1)
Usama ata said:
3 years ago
R=3n(determinate).
R>3n(indeterminate),
R<3n (unstable).
R = no of reaction and N = no of the member.
R>3n(indeterminate),
R<3n (unstable).
R = no of reaction and N = no of the member.
(3)
Rupesh Kumar Yadav said:
4 years ago
Anyone, Explain both Terms.
Saswat sahoo said:
5 years ago
3 hinge arch has D=0 that's why option A is correct.
Nwosu Ferdinand said:
7 years ago
So, what's the degree of freedom for a 3 hinged bar?
Sujatha srinu said:
7 years ago
Why should we add additional equilibrium?
Rahul Kumar singh said:
7 years ago
Since support reactions are 4 and equilibrium equations were 3 and because of a hinge 1 additional equilibrium will be added So,
D = R-S.
R = 4.
S = 3+1 = 4.
D = 4-4 = 0.
Statically determinate.
D = R-S.
R = 4.
S = 3+1 = 4.
D = 4-4 = 0.
Statically determinate.
(2)
Parameshwar said:
8 years ago
We know that D= R-3N.
Here R 6each hing reaction 2 so 3 hinged = 6.
Now mamber = 2.
so put hte value in eqution,
D=6-(3*2),
= 0.
Here R 6each hing reaction 2 so 3 hinged = 6.
Now mamber = 2.
so put hte value in eqution,
D=6-(3*2),
= 0.
(2)
Anwar Kohistani said:
8 years ago
D=R-3N where R=6 b/c of 3 hinges and N=2 two member so D=6-3*2=0.
Karan said:
9 years ago
You are absolutely correct @Mayank.
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