Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 23)
23.
The slenderness ratio of a vertical column of a square cross-section of 2.5 cm sides and 300 cm length, is
Discussion:
33 comments Page 1 of 4.
Tanmoy Ghosh said:
5 years ago
Slenderness Ratio =Le/K,
K=√(I/A).
So,
Le=300,
K=√(2.5^4/12)/(2.5^2),
K=0.7216,
Le/K=300/0.7216,
Slenderness Ratio=415.69.
K=√(I/A).
So,
Le=300,
K=√(2.5^4/12)/(2.5^2),
K=0.7216,
Le/K=300/0.7216,
Slenderness Ratio=415.69.
(5)
Manikanta nelluri said:
5 years ago
@All.
2.5^4÷12 /2.5 * 2.5 = 3.25 ÷ 6.25 = 0.52 this is the correct value.
So, 0.721 this value is wrong.
2.5^4÷12 /2.5 * 2.5 = 3.25 ÷ 6.25 = 0.52 this is the correct value.
So, 0.721 this value is wrong.
(3)
Amit said:
5 years ago
We Know that Slenderness Ratio is Equal to Length upon Radius of Gyration = L/r.
we have a value of L that is given in question 300.
So, now we need to calculate the value of r that is equal to under root I/A means r= under root I/A.
I Means Moment of Inertia, here for Square Section that is equal to a^4/12 and for A= a^4.
Now, you will get the answer 416.
Thank You.
we have a value of L that is given in question 300.
So, now we need to calculate the value of r that is equal to under root I/A means r= under root I/A.
I Means Moment of Inertia, here for Square Section that is equal to a^4/12 and for A= a^4.
Now, you will get the answer 416.
Thank You.
(2)
Susanta sarkar said:
5 years ago
Slenderness ratio=L/k =300/.72=416.
K= √(I/A).
I=bd^3/12 b=d.
I=d^4/12=(2.5) ^4/12/(2.5x2.5) =.52.
K=√.52/6.25=.72.
K= √(I/A).
I=bd^3/12 b=d.
I=d^4/12=(2.5) ^4/12/(2.5x2.5) =.52.
K=√.52/6.25=.72.
(1)
DEVARAJ said:
6 years ago
Slenderness ratio = effective length / radius of gyration.
Radius of gyration = Sqrt(moment of inertia/area of Cross section).
Moment of inertia (I) = b^4/12 (column is a square Cross section).
Assume given length as effective length put All values in the above equations. You will get answer.
Radius of gyration = Sqrt(moment of inertia/area of Cross section).
Moment of inertia (I) = b^4/12 (column is a square Cross section).
Assume given length as effective length put All values in the above equations. You will get answer.
(1)
Ritz said:
7 years ago
Slend. ratio = L(eff)/r(min).
r(min) = ( I(min) / A )^0.5 = 2.5 / 2(3)^0.5
Therefore, S.R = 300 * 2(3)^0.5 / 2.5 = 415.2 closest to 416.
r(min) = ( I(min) / A )^0.5 = 2.5 / 2(3)^0.5
Therefore, S.R = 300 * 2(3)^0.5 / 2.5 = 415.2 closest to 416.
(1)
Raj said:
8 years ago
Can anyone answer?
Slender ness ratio of 5m long column effectively held in position at both ends, but not restrained against rotation and having a circular cross section of the diameter of 5 cm is?
Slender ness ratio of 5m long column effectively held in position at both ends, but not restrained against rotation and having a circular cross section of the diameter of 5 cm is?
Ramana panchadi said:
8 years ago
Slenderness ratio=L effective/Kmin.
K=radius of gyration;K=sq root of i/a;i=moment of intertia @ a=cross sectional area.
k=solid circle=d/4,
K=square=a/2 root 3,
Sol:- K=2.5/2 root 3 =0.7122.
Slenderness ratio=300/0.71222=415.69.
K=radius of gyration;K=sq root of i/a;i=moment of intertia @ a=cross sectional area.
k=solid circle=d/4,
K=square=a/2 root 3,
Sol:- K=2.5/2 root 3 =0.7122.
Slenderness ratio=300/0.71222=415.69.
Manickam said:
8 years ago
Can anyone tell me, The diagram which represents the axial thrust is called?
Debopriyo pal said:
8 years ago
Thanks for the answer.
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