Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 23)
23.
The slenderness ratio of a vertical column of a square cross-section of 2.5 cm sides and 300 cm length, is
Discussion:
33 comments Page 2 of 4.
U Kumar said:
8 years ago
Thanks @Subhankar.
Yamiiiii said:
7 years ago
S.R=Equivalent length of column or unsupported length/least radius of gyration
=Le/k,
=Le/√(I/A).
√[I/A] =root[(2.5/12)*(1/2.5)],
=0.72168783654321698610321.
S.R=300/0.72168783654321698610321.
S.R=415.6921938=415. 69=416.
=Le/k,
=Le/√(I/A).
√[I/A] =root[(2.5/12)*(1/2.5)],
=0.72168783654321698610321.
S.R=300/0.72168783654321698610321.
S.R=415.6921938=415. 69=416.
Jahangir badini said:
7 years ago
Slenderness ratio : L/√bh*3/12/area.
Someshwar said:
7 years ago
S.R =eff. length/radius of gyration.
=l/k.
K= √ Imin/A.
Imin=bd^3/12=2.5*2.5^3/12=3.25.
A=2.5*2.5=6.25,
=√3.25/6.25 =0.721.
S.R=300/0.721 =416.08.
=l/k.
K= √ Imin/A.
Imin=bd^3/12=2.5*2.5^3/12=3.25.
A=2.5*2.5=6.25,
=√3.25/6.25 =0.721.
S.R=300/0.721 =416.08.
Pantlok said:
6 years ago
Effec length =300,
Radius of gyration=((a^4/12)/a^2),
S.R=effec. length/radius of gyration (ans: 415.69)
Radius of gyration=((a^4/12)/a^2),
S.R=effec. length/radius of gyration (ans: 415.69)
Kumud Chaudhary said:
6 years ago
I = A * r.
2.5^4/12=2.5 * 2.5 * r.
r = 0.72168.
Now slenderness ratio= l/r.
= 300/0.72168.
= 415.74.
So answer is correct.
2.5^4/12=2.5 * 2.5 * r.
r = 0.72168.
Now slenderness ratio= l/r.
= 300/0.72168.
= 415.74.
So answer is correct.
Sachin said:
6 years ago
Thanks all for explaining.
Kaushal said:
1 decade ago
According to me, Slenderness ratio is kl/b. where k is length factor, l is the length of column and b is the width.
Let us suppose k = 1 (pin jointed both sides).
Slenderness ratio = 1*300/2.5 = 120.
How could answer be 416?
Let us suppose k = 1 (pin jointed both sides).
Slenderness ratio = 1*300/2.5 = 120.
How could answer be 416?
Bikash Kabiraj said:
8 years ago
Slenderness ratio = effective length/radius of gyration.
Radius of gyration = under root of i/a,
i = moment of inertia and a =cross sectionl area. i=2.5^4/12= and a = 2.5^2.
So radius of gyration = 0.721.
Soslenderness ratio=300/0.721 = 416.088.
Radius of gyration = under root of i/a,
i = moment of inertia and a =cross sectionl area. i=2.5^4/12= and a = 2.5^2.
So radius of gyration = 0.721.
Soslenderness ratio=300/0.721 = 416.088.
Kishan said:
9 years ago
Slenderness ratio = left/rmin.
Rmin=I/A for square section a/2*√3=2.5/2√3 = 0.72 leff = 300cm then slenderness is;
= 300/0.72= 416.67ans.
Rmin=I/A for square section a/2*√3=2.5/2√3 = 0.72 leff = 300cm then slenderness is;
= 300/0.72= 416.67ans.
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