Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 23)
23.
The slenderness ratio of a vertical column of a square cross-section of 2.5 cm sides and 300 cm length, is
Discussion:
33 comments Page 4 of 4.
Pawan kumar said:
1 decade ago
You are right @Pradhyumna.
Slenderness ratio = l/k = 300/0.7217= 415.692=416.
K = radius of gyration = root under(I/A) = under root 0.52.
I/A = (moment of inertia/area) = 2.5*2.5*2.5*2.5/12)/(2.5*2.5)=0.52.
Slenderness ratio = l/k = 300/0.7217= 415.692=416.
K = radius of gyration = root under(I/A) = under root 0.52.
I/A = (moment of inertia/area) = 2.5*2.5*2.5*2.5/12)/(2.5*2.5)=0.52.
Pradhyumna said:
1 decade ago
Dear @Kaushal, clear the definition first.
Slenderness ratio = Unsupported length of column/minimum radius of gyration of cross-section.
Hence, SR = 300/rad. of gyration.
= 300/ sq.root of ((2.5^4/(12*2.5^2))).
= 415.692.
= 416.
Slenderness ratio = Unsupported length of column/minimum radius of gyration of cross-section.
Hence, SR = 300/rad. of gyration.
= 300/ sq.root of ((2.5^4/(12*2.5^2))).
= 415.692.
= 416.
Raju said:
1 decade ago
kl = 300.
r = (i%a)0.5.
Slender ratio = kl%r.
i = moment of inertia = b*d3%12.
a = cross section area = 2.2*2.5.
r = (i%a)0.5.
Slender ratio = kl%r.
i = moment of inertia = b*d3%12.
a = cross section area = 2.2*2.5.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers