Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 12)
12.
A cantilever beam rectangular in cross-section is subjected to an isolated load at its free end. If the width of the beam is doubled, the deflection of the free end will be changed in the ratio of
Discussion:
14 comments Page 1 of 2.
Jaz said:
6 years ago
1/2.
Definition=wl^3/3EI.
I=bd^3/12 for rectangular section according to question b=2b.
So, the deflection =1/2.
Definition=wl^3/3EI.
I=bd^3/12 for rectangular section according to question b=2b.
So, the deflection =1/2.
(1)
Khurshid said:
6 years ago
Should deflection decrease on increasing width or decrease?
(1)
Mounika reddy said:
1 decade ago
y1 = MX^2/2EI For b.
I = bh^3/12 if b = 2b.
I = 2bh^3/12.
y2 = MX^2/4EI FOR 2b.
y2 = 1/2(y1).
I = bh^3/12 if b = 2b.
I = 2bh^3/12.
y2 = MX^2/4EI FOR 2b.
y2 = 1/2(y1).
Dhanu said:
8 years ago
@Mounika Reddy.
Deflection is wl^3/3EI.
Not wl^2/2EI.
Deflection is wl^3/3EI.
Not wl^2/2EI.
Shubham verma said:
8 years ago
D diflection.
D1=PL^3/3EI
IF L=2L
THEN
D2=P(2L)^3/3EI
D2=8PL^3/3EI
D2=8D1
SO
D1/D2=1/8.
D1=PL^3/3EI
IF L=2L
THEN
D2=P(2L)^3/3EI
D2=8PL^3/3EI
D2=8D1
SO
D1/D2=1/8.
Paul said:
8 years ago
Pl3/3EI.
I = bd3/12 in 1st case ( d3 = cube of d).
I = 2bd3/12 in 2nd case,
The ratio will come as 2.
So, option D is correct.
I = bd3/12 in 1st case ( d3 = cube of d).
I = 2bd3/12 in 2nd case,
The ratio will come as 2.
So, option D is correct.
Alex said:
8 years ago
Y1= WL^3/3EIx.
Ix = bd^3/12.
Now for b = 2b.
Iy = 2bd^3/12.
Iy = 2 Ix.
Now Y2 = WL^3/3EIy or WL^3/3E(2Ix)
Y2 = 1/2( WL^3/3EIx)
Y2 = 1/2 Y1.
So, option C correct.
Ix = bd^3/12.
Now for b = 2b.
Iy = 2bd^3/12.
Iy = 2 Ix.
Now Y2 = WL^3/3EIy or WL^3/3E(2Ix)
Y2 = 1/2( WL^3/3EIx)
Y2 = 1/2 Y1.
So, option C correct.
Pintu kumar said:
7 years ago
Option D is the correct answer.
Amol said:
7 years ago
Option D correct.
{4wl^3÷Ebd ^3}÷{2wl ^3÷E bd ^3}= 2.
{4wl^3÷Ebd ^3}÷{2wl ^3÷E bd ^3}= 2.
Ravi said:
7 years ago
Deflection of the cantilever is PL^3/3EI.
So, i=bd^3/12 according to the quetions ratio ( bd^3/12 )/(2bd^3/12) =1/2 is the answer.
So, i=bd^3/12 according to the quetions ratio ( bd^3/12 )/(2bd^3/12) =1/2 is the answer.
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