Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 12)
12.
A cantilever beam rectangular in cross-section is subjected to an isolated load at its free end. If the width of the beam is doubled, the deflection of the free end will be changed in the ratio of
Discussion:
14 comments Page 1 of 2.
Kaushik Nandan Baruah said:
3 years ago
Deflection will increase on increasing width and decrease on increasing depth.
Khurshid said:
6 years ago
Should deflection decrease on increasing width or decrease?
(1)
Adarsh vishwakarma said:
6 years ago
Deflection at free end Y = pL^3/(2EI).
= 1/2.
= 1/2.
Jaz said:
6 years ago
1/2.
Definition=wl^3/3EI.
I=bd^3/12 for rectangular section according to question b=2b.
So, the deflection =1/2.
Definition=wl^3/3EI.
I=bd^3/12 for rectangular section according to question b=2b.
So, the deflection =1/2.
(1)
SUMIT said:
6 years ago
Deflection.
For point load, deflection (proportional) -> l^3/bd^3.
For udl deflection (proportional) -> l^4/bd^3.
For point load, deflection (proportional) -> l^3/bd^3.
For udl deflection (proportional) -> l^4/bd^3.
Anamika said:
6 years ago
Deflection of the cantilever is PL^3/3EI.
So, i=bd^3/12 according to the quetions ratio ( bd^3/12 )/(2b(2d)^3/12) =1/16,
ia/ib=0.0625.
ia/ib= 6.25% is the answer.
So, i=bd^3/12 according to the quetions ratio ( bd^3/12 )/(2b(2d)^3/12) =1/16,
ia/ib=0.0625.
ia/ib= 6.25% is the answer.
Ravi said:
7 years ago
Deflection of the cantilever is PL^3/3EI.
So, i=bd^3/12 according to the quetions ratio ( bd^3/12 )/(2bd^3/12) =1/2 is the answer.
So, i=bd^3/12 according to the quetions ratio ( bd^3/12 )/(2bd^3/12) =1/2 is the answer.
Amol said:
7 years ago
Option D correct.
{4wl^3÷Ebd ^3}÷{2wl ^3÷E bd ^3}= 2.
{4wl^3÷Ebd ^3}÷{2wl ^3÷E bd ^3}= 2.
Pintu kumar said:
7 years ago
Option D is the correct answer.
Alex said:
8 years ago
Y1= WL^3/3EIx.
Ix = bd^3/12.
Now for b = 2b.
Iy = 2bd^3/12.
Iy = 2 Ix.
Now Y2 = WL^3/3EIy or WL^3/3E(2Ix)
Y2 = 1/2( WL^3/3EIx)
Y2 = 1/2 Y1.
So, option C correct.
Ix = bd^3/12.
Now for b = 2b.
Iy = 2bd^3/12.
Iy = 2 Ix.
Now Y2 = WL^3/3EIy or WL^3/3E(2Ix)
Y2 = 1/2( WL^3/3EIx)
Y2 = 1/2 Y1.
So, option C correct.
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