Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 9)
9.
The shape of the bending moment diagram over the length of a beam, having no external load, is always
Discussion:
36 comments Page 1 of 4.
Sivanarayana said:
1 year ago
The answer is parabola, why because in any beam i.e. SS beam, the cantilever beam self-weight of the beam is UDL only.
In that case, BMD is parabola. Note that in any design calculations, we are taking dead weight into account for calculations in fixing size steel calculations and other parameters.
In that case, BMD is parabola. Note that in any design calculations, we are taking dead weight into account for calculations in fixing size steel calculations and other parameters.
(1)
Sunil said:
10 years ago
Parabola is correct answer because when any external load is not subjected to the beam so beam is acting only self weight and self weight is always in the form of udl and we known that for udl loading bmd is parabolic and smd is inclined.
Neelam shekhawat said:
1 decade ago
If the beam having no external load then it would not be bend. So shape always will be liner. And self weight will be act as udl but it does not change the shape because beam carries its weight without any bending.
Sryadav said:
7 years ago
Tell me one thing please when you neglect self-weight than without external loading which type of load acting on the beam so bending moment in the beam is linear?
So, the correct answer is parabolic.
So, the correct answer is parabolic.
(2)
Naren said:
9 years ago
We know that self-weight is UDL and UDL BM is parabola.
Here, the answer is the parabola (when self-weight should be considered) or it must be linear (when self-weight should not be considered).
Here, the answer is the parabola (when self-weight should be considered) or it must be linear (when self-weight should not be considered).
Uzair ahmed said:
5 years ago
No, the external load doesn't mean that beam is resting with weightlessness and levitating in the air, indeed, the dead load will be considered as UDL, and for UDL BMD is definitely parabola.
(1)
Dalisha said:
9 years ago
Linear is correct because if we consider its self-weight as udl then for finding sfd and bmd by external loads we must consider its self-weight also and give its effect combined with udl.
Krishna sharma said:
9 years ago
For finding bending moment and shear force in the beam, we do not consider the self-weight of the beam that why in the case of no external load. Bending moment diagram will linear.
Ishu said:
6 years ago
How will you get linear if no load at all (neglecting self wt)?.
In that case, BM=0. If there is some concentrated Moment then it must be linear (ie constant horizontal line).
In that case, BM=0. If there is some concentrated Moment then it must be linear (ie constant horizontal line).
Sneha said:
5 years ago
Here it is asking for BMD and it will not consider self-weight while drawing. So, here BMD will be a straight horizontal line. And in that sense, it is taken as linear.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers