Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 9)
9.
The shape of the bending moment diagram over the length of a beam, having no external load, is always
Discussion:
36 comments Page 1 of 4.
BIBEK GUPTA said:
1 decade ago
If the beam having no external load then self weight will be act as udl throughout the entire span, for that reason the BM diagram will be parabola.
Neelam shekhawat said:
1 decade ago
If the beam having no external load then it would not be bend. So shape always will be liner. And self weight will be act as udl but it does not change the shape because beam carries its weight without any bending.
Vinay said:
1 decade ago
Yes I agree it is parabola since the dead load of the beam is UDL.
Diwakar said:
1 decade ago
Yes I think parabola is correct answer.
Harish said:
1 decade ago
In a theory it states that beam linear before application of load (self weight is neglected) so linear is correct.
Devi said:
1 decade ago
I think Parabola answer is correct.
N adeppa said:
10 years ago
Linear is correct. Self weight of beam act as point load at its center as in case of ssb, hence bending moment is linear in variation.
Salil gurudev said:
10 years ago
If self with neglected then answer will be linear.
But if self with include answer will be parabola.
But if self with include answer will be parabola.
Sunil said:
10 years ago
Parabola is correct answer because when any external load is not subjected to the beam so beam is acting only self weight and self weight is always in the form of udl and we known that for udl loading bmd is parabolic and smd is inclined.
Mujru said:
9 years ago
Here no act loading in this beam so the corect answer is Linear (here self weight of the beam are no prefer).
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