Civil Engineering - Steel Structure Design - Discussion
Discussion Forum : Steel Structure Design - Section 1 (Q.No. 32)
32.
The average shear stress for rolled steel beam section, is
Discussion:
12 comments Page 1 of 2.
Arti said:
8 years ago
0.4*2400=960.
(2)
Ankhs said:
9 years ago
Anyone explain it please.
(1)
Suriya janak said:
9 years ago
The average shear stress in structural steel is 0.4fy.
So, consider fy = 2400 kpa.
Hence Avg. shear stress = 0.4 * 2400 = 980 kpa.
So, B or C.
So, consider fy = 2400 kpa.
Hence Avg. shear stress = 0.4 * 2400 = 980 kpa.
So, B or C.
(1)
Jazz said:
6 years ago
Avg shear stress = ( 0.4*230 +0.4*240 +0.4*250)/3.
= 945kg/cm2.
= 945kg/cm2.
(1)
Kailash said:
8 years ago
Anyone explain this please.
Deep said:
7 years ago
Why we can't consider 250 mpa as fy?
For matching answer is right.
For matching answer is right.
Sanchit said:
7 years ago
Because they take the beam whose thickness is more than 20mm and less than 40mm.
Raj said:
7 years ago
960 is the corect answer.
.4 * 240=96 mpa=96 * 10 = 960kg/cm2.
.4 * 240=96 mpa=96 * 10 = 960kg/cm2.
Amu bokato said:
6 years ago
@Raj.
How 240? Explain.
How 240? Explain.
Rahul Ghogare said:
6 years ago
@Amu Bokato
If the thickness of member is less than 20 mm then Fy is 250 Mpa.
For 20-40 mm, Fy is taken as 240 Mpa.
For t > 40mm, fy is 230 Mpa.
If the thickness of member is less than 20 mm then Fy is 250 Mpa.
For 20-40 mm, Fy is taken as 240 Mpa.
For t > 40mm, fy is 230 Mpa.
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