Civil Engineering - Steel Structure Design - Discussion

Discussion :: Steel Structure Design - Section 1 (Q.No.32)

32.

The average shear stress for rolled steel beam section, is

 [A]. 845 kg/cm2 [B]. 945 kg/cm2 [C]. 1025 kg/cm2 [D]. 1500 kg/cm2 [E]. 1875 kg/cm2

Explanation:

No answer description available for this question.

 Ankhs said: (Oct 2, 2016) Anyone explain it please.

 Suriya Janak said: (Dec 23, 2016) The average shear stress in structural steel is 0.4fy. So, consider fy = 2400 kpa. Hence Avg. shear stress = 0.4 * 2400 = 980 kpa. So, B or C.

 Kailash said: (Oct 3, 2017) Anyone explain this please.

 Arti said: (Dec 9, 2017) 0.4*2400=960.

 Deep said: (Mar 15, 2018) Why we can't consider 250 mpa as fy? For matching answer is right.

 Sanchit said: (Mar 21, 2018) Because they take the beam whose thickness is more than 20mm and less than 40mm.

 Raj said: (Oct 16, 2018) 960 is the corect answer. .4 * 240=96 mpa=96 * 10 = 960kg/cm2.

 Amu Bokato said: (Mar 10, 2019) @Raj. How 240? Explain.

 Rahul Ghogare said: (Aug 11, 2019) @Amu Bokato If the thickness of member is less than 20 mm then Fy is 250 Mpa. For 20-40 mm, Fy is taken as 240 Mpa. For t > 40mm, fy is 230 Mpa.

 Sabir said: (Dec 19, 2019) .4fy average shear stress and .44fy for shear stress (.4x250=100N/mm^2). 100x9.81=981kg/mm^2.

 Jazz said: (Dec 20, 2019) Avg shear stress = ( 0.4*230 +0.4*240 +0.4*250)/3. = 945kg/cm2.