Civil Engineering - Steel Structure Design - Discussion
Discussion Forum : Steel Structure Design - Section 2 (Q.No. 11)
11.
Strengths of a rivet in single shearing, in bearing and in tearing are 3425 kg, 4575 kg and 5025 kg respectively. If the load in the member is 35 tonnes, the number of rivets required, is
Discussion:
23 comments Page 1 of 3.
Rakesh said:
8 years ago
Bearing, shearing, and tearing strength is called Rivet value.
In bearing tearing and shearing value we take always Lower value whichever is less
Here my Rivet value is= 3428kg.
Load is = 35tonnes =35x1000=35000.
Then,
No of Rivet= load/ rivet value.
Then,
35000/3425= 10.22.
We can say 11 rivet.
In bearing tearing and shearing value we take always Lower value whichever is less
Here my Rivet value is= 3428kg.
Load is = 35tonnes =35x1000=35000.
Then,
No of Rivet= load/ rivet value.
Then,
35000/3425= 10.22.
We can say 11 rivet.
(2)
Parth said:
7 years ago
While calculating the shear and bearing capacity of rivet the factor of safety had been calculated. Is it necessary to consider the factor of safety twice? Please, anyone, tell me.
Rohan Mukherjee said:
5 years ago
The answer is wrong!
Rivet value is taken as minimum value of Shearing, Bearing and tearing!
No of rivets = Force/Rivet value.
Then the answer is 10.21.
Rivet value is taken as minimum value of Shearing, Bearing and tearing!
No of rivets = Force/Rivet value.
Then the answer is 10.21.
Atif Saeed said:
9 years ago
Load Factor of 1.2 gives total load as 35 * 1.2 * 1000 = 42000 kg. Hence the Number of Rivets = 42,000/3425 = 12.26.
So, 13 Rivets are required.
So, 13 Rivets are required.
Selvi said:
8 years ago
No of rivet = load/rivet vale.
Rivet value is the least value of bearing and shearing.
SO, n = 35000/3425 = 10.22 say 11.
Rivet value is the least value of bearing and shearing.
SO, n = 35000/3425 = 10.22 say 11.
Priya said:
8 years ago
We know number of rivet = force /rivet value.
But here shearing, tearing many value given how can solve explain it.
But here shearing, tearing many value given how can solve explain it.
Pavan said:
8 years ago
Rivets are used in WSM method. So why we multiply the load by load factor?
Then answer is 11.
Then answer is 11.
Ravi kumar vishwakarma said:
8 years ago
The answer should be 11 because;
n = load/rivet value.
n = 35000/3425,
n = 10.2 = 11.
n = load/rivet value.
n = 35000/3425,
n = 10.2 = 11.
Arnab said:
1 decade ago
n=p/Rv so from the formula 35000/3425=10.22. So answer should be between a&b.
Shashank said:
1 decade ago
n = load applied/least strength of rivet = 35000/3425 = 10.22 = 11 rivet.
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