### Discussion :: Steel Structure Design - Section 2 (Q.No.11)

Arnab said: (Aug 6, 2014) | |

n=p/Rv so from the formula 35000/3425=10.22. So answer should be between a&b. |

Shashank said: (Dec 1, 2014) | |

n = load applied/least strength of rivet = 35000/3425 = 10.22 = 11 rivet. |

Rajesh said: (Sep 5, 2015) | |

But the answer shows 13. |

Pranjal said: (Jan 26, 2016) | |

Shearing strength = 3425/1.25. Answer 13. |

Lal Bir said: (Sep 2, 2016) | |

From where 1.25 comes? |

Rabbi Dhillon said: (Nov 10, 2016) | |

1.25P/least strength of rivet. 1.25 * 35000/3425 = 12.773. |

Atif Saeed said: (Feb 19, 2017) | |

Load Factor of 1.2 gives total load as 35 * 1.2 * 1000 = 42000 kg. Hence the Number of Rivets = 42,000/3425 = 12.26. So, 13 Rivets are required. |

Ankit said: (Mar 17, 2017) | |

Why 1.25 is multiplied in 35000? |

M. Farooq said: (May 3, 2017) | |

1.25 is Factor of safety. FOS= 1.25. |

Prateek said: (May 28, 2017) | |

Always even num of rivets are provided so 12 num of rivets is required. |

Ravi Kumar Vishwakarma said: (Jun 5, 2017) | |

The answer should be 11 because; n = load/rivet value. n = 35000/3425, n = 10.2 = 11. |

Selvi said: (Jul 7, 2017) | |

No of rivet = load/rivet vale. Rivet value is the least value of bearing and shearing. SO, n = 35000/3425 = 10.22 say 11. |

Pavan said: (Jul 19, 2017) | |

Rivets are used in WSM method. So why we multiply the load by load factor? Then answer is 11. |

Priya said: (Nov 10, 2017) | |

We know number of rivet = force /rivet value. But here shearing, tearing many value given how can solve explain it. |

Dipak said: (Nov 26, 2017) | |

11 is the right answer. |

Rakesh said: (Dec 5, 2017) | |

Bearing, shearing, and tearing strength is called Rivet value. In bearing tearing and shearing value we take always Lower value whichever is less Here my Rivet value is= 3428kg. Load is = 35tonnes =35x1000=35000. Then, No of Rivet= load/ rivet value. Then, 35000/3425= 10.22. We can say 11 rivet. |

Viru Kapoor said: (Mar 7, 2018) | |

Guys it's 13. Take fOS also. |

Deep said: (Mar 15, 2018) | |

It is 11. And no need to add FOS for matching with answer. |

Amit Kumar said: (Apr 1, 2018) | |

Agree @Deep. It should be 11. |

Manu said: (Apr 5, 2018) | |

Yes, I also agree @Deep. It is no need of FOS. |

Parth said: (Oct 24, 2018) | |

While calculating the shear and bearing capacity of rivet the factor of safety had been calculated. Is it necessary to consider the factor of safety twice? Please, anyone, tell me. |

Veer said: (Feb 20, 2020) | |

No need to use FOS because of strength is already underestimated. |

Rohan Mukherjee said: (Aug 26, 2020) | |

The answer is wrong! Rivet value is taken as minimum value of Shearing, Bearing and tearing! No of rivets = Force/Rivet value. Then the answer is 10.21. |

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