Civil Engineering - Steel Structure Design - Discussion

Discussion Forum : Steel Structure Design - Section 2 (Q.No. 11)
11.
Strengths of a rivet in single shearing, in bearing and in tearing are 3425 kg, 4575 kg and 5025 kg respectively. If the load in the member is 35 tonnes, the number of rivets required, is
10
11
12
13
15
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
23 comments Page 1 of 3.

Rakesh said:   8 years ago
Bearing, shearing, and tearing strength is called Rivet value.

In bearing tearing and shearing value we take always Lower value whichever is less

Here my Rivet value is= 3428kg.
Load is = 35tonnes =35x1000=35000.

Then,
No of Rivet= load/ rivet value.
Then,
35000/3425= 10.22.

We can say 11 rivet.
(2)

Deep said:   7 years ago
It is 11. And no need to add FOS for matching with answer.
(1)

Selvi said:   8 years ago
No of rivet = load/rivet vale.

Rivet value is the least value of bearing and shearing.

SO, n = 35000/3425 = 10.22 say 11.

Rohan Mukherjee said:   5 years ago
The answer is wrong!

Rivet value is taken as minimum value of Shearing, Bearing and tearing!
No of rivets = Force/Rivet value.
Then the answer is 10.21.

Veer said:   6 years ago
No need to use FOS because of strength is already underestimated.

Parth said:   7 years ago
While calculating the shear and bearing capacity of rivet the factor of safety had been calculated. Is it necessary to consider the factor of safety twice? Please, anyone, tell me.

Manu said:   7 years ago
Yes, I also agree @Deep.

It is no need of FOS.

Amit kumar said:   7 years ago
Agree @Deep.

It should be 11.

Viru kapoor said:   7 years ago
Guys it's 13.

Take fOS also.

Dipak said:   8 years ago
11 is the right answer.


Post your comments here:

Your comments will be displayed after verification.