Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 9)
9.
A pile is being driven with a drop hammer weighing 1800 kg and having a free fall of 1.00 m. If the penetration with last blow is 5 mm, the load carrying capacity of the pile, -according to the Engineering News formula, is
100 tonnes
50 tonnes
20 tonnes
10 tonnes.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
22 comments Page 1 of 3.

Sibbu sahu said:   2 years ago
Engineering news formula:-
Qu=WH/6(S+C).

W= 1800kg,
H= 1m (100cm).
S= 5mm (0.5cm)
C=2.5cm(drop hammer).

Qu = 1800*100/6(0.5+2.5).
Qu = 10000kg.
Qu = 10 tonnes.
(7)

Abhay said:   10 years ago
As per the Engineering News formula the allowable load of driven pile is given by:

Qa = Wh/{F(s+c)}.

Where, Qa = Allowable load in kg.

W = Weight of hammer = 1800 kg.

h = Height of fall in cms = 1.00 m = 100 cm.

s = Final settlement per blow known as set = 5 mm = 0.5 cm.

c = Empirical constant (c = 2.5 cm for drop hammer).

F = Factor of safety (Usually taken as 6).

Qa = 1800*100/{6*(0.5 + 2.5)}.

= 1800*100/18.

= 10000 kg.

= 10 tonne.
(5)

Sultan Fareed Shahwani said:   2 years ago
Using the formula WH/S+C*FOS.
So,
C=5mm it is taken in cm = 50cm.

For Drop hammer number of blows = 5.
Given Data
W=1800 , C= 50cm , H= 1m, S= 5blows

Solution:
1800*1/50+5*6 = 1800/180 = 10 tonnes => Answer.
(4)

Geetika said:   2 years ago
I am not understanding. Please explain me.
(1)

Monalisha said:   10 years ago
What is 'C' and how we can take UTS value?
(1)

Riya said:   3 years ago
Well explained, Thanks @Abhaya.
(1)

Faasi said:   6 years ago
Thanks @Abhay.

Tanmoy Karmakar said:   4 years ago
Thank you for explaining the answer @Abhay.

Sunny said:   4 years ago
Why to take F. O. S as the question didn't mention allowable load carrying capacity and ultimate load carrying capacity?

Thaiba said:   4 years ago
Thanks all.


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