Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 9)
9.
A pile is being driven with a drop hammer weighing 1800 kg and having a free fall of 1.00 m. If the penetration with last blow is 5 mm, the load carrying capacity of the pile, -according to the Engineering News formula, is
Discussion:
22 comments Page 1 of 3.
Pratima Yadav said:
1 decade ago
Engineering News Formula,
Q = W*h/ (s+c).
Where,
Q = Energy loss.
W = weight of the ram.
h = fall height of the ram (inches).
s = measured penetration of the pile per blow (inches).
c = 0.1.
Q = W*h/ (s+c).
Where,
Q = Energy loss.
W = weight of the ram.
h = fall height of the ram (inches).
s = measured penetration of the pile per blow (inches).
c = 0.1.
Abdul latif nasar said:
1 decade ago
Dear by this formula it become 6.08.
Deep said:
1 decade ago
W=1800 kg.
H=100 cm.
F=6 (factor of safety).
S=0.5cm penetration.
C=2.5(for drop hammer).
Load = WH/(F(S+C)) kg.
= 10000kg.
H=100 cm.
F=6 (factor of safety).
S=0.5cm penetration.
C=2.5(for drop hammer).
Load = WH/(F(S+C)) kg.
= 10000kg.
10 tonnes said:
1 decade ago
W = 1000 kg.
H = 1 m = 100 cm.
F = 6.
S = 0.5 cm.
And C = 2.5.
Now formula is: W*H/ (S+C) = 10 tonnes.
H = 1 m = 100 cm.
F = 6.
S = 0.5 cm.
And C = 2.5.
Now formula is: W*H/ (S+C) = 10 tonnes.
Monalisha said:
10 years ago
What is 'C' and how we can take UTS value?
(1)
Mann said:
10 years ago
For drop hammer we use c = 2.5. So correct answer is 10 tonne.
Samrat said:
10 years ago
Dear @Mann.
Can you elaborate how you get the answer 10 tonne?
What FOS you have taken? Is it F = 10/3?
Can you elaborate how you get the answer 10 tonne?
What FOS you have taken? Is it F = 10/3?
Abhay said:
10 years ago
As per the Engineering News formula the allowable load of driven pile is given by:
Qa = Wh/{F(s+c)}.
Where, Qa = Allowable load in kg.
W = Weight of hammer = 1800 kg.
h = Height of fall in cms = 1.00 m = 100 cm.
s = Final settlement per blow known as set = 5 mm = 0.5 cm.
c = Empirical constant (c = 2.5 cm for drop hammer).
F = Factor of safety (Usually taken as 6).
Qa = 1800*100/{6*(0.5 + 2.5)}.
= 1800*100/18.
= 10000 kg.
= 10 tonne.
Qa = Wh/{F(s+c)}.
Where, Qa = Allowable load in kg.
W = Weight of hammer = 1800 kg.
h = Height of fall in cms = 1.00 m = 100 cm.
s = Final settlement per blow known as set = 5 mm = 0.5 cm.
c = Empirical constant (c = 2.5 cm for drop hammer).
F = Factor of safety (Usually taken as 6).
Qa = 1800*100/{6*(0.5 + 2.5)}.
= 1800*100/18.
= 10000 kg.
= 10 tonne.
(5)
@rocky said:
9 years ago
C is known as elastic compression.
Ravindra said:
7 years ago
S -5 blow for drop hammer.
And 20 blow for a steam hammer.
C -2.5 for drop hammer in cm.
And .25 for steam hammer.
Q= W(load in kg)*H(free fall in cm)/Fos*(S+C).
And 20 blow for a steam hammer.
C -2.5 for drop hammer in cm.
And .25 for steam hammer.
Q= W(load in kg)*H(free fall in cm)/Fos*(S+C).
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