Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 9)
9.
A pile is being driven with a drop hammer weighing 1800 kg and having a free fall of 1.00 m. If the penetration with last blow is 5 mm, the load carrying capacity of the pile, -according to the Engineering News formula, is
Discussion:
22 comments Page 1 of 3.
Sibbu sahu said:
2 years ago
Engineering news formula:-
Qu=WH/6(S+C).
W= 1800kg,
H= 1m (100cm).
S= 5mm (0.5cm)
C=2.5cm(drop hammer).
Qu = 1800*100/6(0.5+2.5).
Qu = 10000kg.
Qu = 10 tonnes.
Qu=WH/6(S+C).
W= 1800kg,
H= 1m (100cm).
S= 5mm (0.5cm)
C=2.5cm(drop hammer).
Qu = 1800*100/6(0.5+2.5).
Qu = 10000kg.
Qu = 10 tonnes.
(7)
Sultan Fareed Shahwani said:
2 years ago
Using the formula WH/S+C*FOS.
So,
C=5mm it is taken in cm = 50cm.
For Drop hammer number of blows = 5.
Given Data
W=1800 , C= 50cm , H= 1m, S= 5blows
Solution:
1800*1/50+5*6 = 1800/180 = 10 tonnes => Answer.
So,
C=5mm it is taken in cm = 50cm.
For Drop hammer number of blows = 5.
Given Data
W=1800 , C= 50cm , H= 1m, S= 5blows
Solution:
1800*1/50+5*6 = 1800/180 = 10 tonnes => Answer.
(4)
Geetika said:
2 years ago
I am not understanding. Please explain me.
(1)
Riya said:
3 years ago
Well explained, Thanks @Abhaya.
(1)
Tanmoy Karmakar said:
4 years ago
Thank you for explaining the answer @Abhay.
Sunny said:
4 years ago
Why to take F. O. S as the question didn't mention allowable load carrying capacity and ultimate load carrying capacity?
Thaiba said:
4 years ago
Thanks all.
Dheeraj said:
6 years ago
Thanks @Abhay.
Aryan said:
6 years ago
Thanks all for explaining.
Reka said:
6 years ago
Thanks, @Abhay.
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