Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 2)
2.
The active earth pressure of a soil is proportional to (where φ is the angle of friction of the soil)
Discussion:
21 comments Page 3 of 3.
ViVEK said:
2 years ago
Ka = (1-sin¢)/(1+sin ¢)
= Cot^2 (Alpha) = Cot^2 (45+¢/2)
=Cot^2 [90-(45-¢/2)]
={Cot [90-(45-¢/2)]}^2
= {tan(45-¢/2)}^2
= tan^2 (45-¢/2)
Kp = (1+sin¢) / (1-sin¢)
= tan^2 (Alpha) = tan^2 (45+¢/2)
=>In active earth pressure failure plane make angle of 45+¢/2 with horizontal .
=>In the Passive earth pressure, failure plane makes an angle of 45-¢/2 with horizontal.
=> Remember that angles are not indicated of Alpha.
In the above formulas, Alpha is the Critical Angle.
= Cot^2 (Alpha) = Cot^2 (45+¢/2)
=Cot^2 [90-(45-¢/2)]
={Cot [90-(45-¢/2)]}^2
= {tan(45-¢/2)}^2
= tan^2 (45-¢/2)
Kp = (1+sin¢) / (1-sin¢)
= tan^2 (Alpha) = tan^2 (45+¢/2)
=>In active earth pressure failure plane make angle of 45+¢/2 with horizontal .
=>In the Passive earth pressure, failure plane makes an angle of 45-¢/2 with horizontal.
=> Remember that angles are not indicated of Alpha.
In the above formulas, Alpha is the Critical Angle.
(11)
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