Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 2)
2.
The active earth pressure of a soil is proportional to (where φ is the angle of friction of the soil)
Discussion:
21 comments Page 2 of 3.
Sanjay said:
8 years ago
tan2(45+π/2).
Where π=angle of friction.
Where π=angle of friction.
Akhil said:
7 years ago
Active earth pressure = 1/(tan2 (45° + π/2)) = tan2 (45° + π/2)
ka = 1/ kp.
ka = 1/ kp.
(2)
Sudipta said:
7 years ago
ka=1/tan^2(45°+Φ/2).
=tan^2(45°+Φ/2).
=flow value.
=tan^2(45°+Φ/2).
=flow value.
Paul said:
7 years ago
What will be for soil at rest?
Staffana aishwarya said:
7 years ago
Soil at rest K0 = 1 - sinΠ.
Mahesh said:
6 years ago
How to calculate the angle? Please, anyone, tell me.
Manoj said:
4 years ago
According to me, Pa is proportional to cot^2(45+π/2).
Harsh Shah said:
3 years ago
What will be for passive earth pressure of soil? Please explain.
Joseph Nigus said:
3 years ago
The correct answer is option B.
(1)
Ravi said:
2 years ago
I think this term is also called flow value.
(1)
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