Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 2)
2.
The active earth pressure of a soil is proportional to (where φ is the angle of friction of the soil)
Discussion:
21 comments Page 1 of 3.
ViVEK said:
2 years ago
Ka = (1-sin¢)/(1+sin ¢)
= Cot^2 (Alpha) = Cot^2 (45+¢/2)
=Cot^2 [90-(45-¢/2)]
={Cot [90-(45-¢/2)]}^2
= {tan(45-¢/2)}^2
= tan^2 (45-¢/2)
Kp = (1+sinĀ¢) / (1-sin¢)
= tan^2 (Alpha) = tan^2 (45+¢/2)
=>In active earth pressure failure plane make angle of 45+¢/2 with horizontal .
=>In the Passive earth pressure, failure plane makes an angle of 45-¢/2 with horizontal.
=> Remember that angles are not indicated of Alpha.
In the above formulas, Alpha is the Critical Angle.
= Cot^2 (Alpha) = Cot^2 (45+¢/2)
=Cot^2 [90-(45-¢/2)]
={Cot [90-(45-¢/2)]}^2
= {tan(45-¢/2)}^2
= tan^2 (45-¢/2)
Kp = (1+sinĀ¢) / (1-sin¢)
= tan^2 (Alpha) = tan^2 (45+¢/2)
=>In active earth pressure failure plane make angle of 45+¢/2 with horizontal .
=>In the Passive earth pressure, failure plane makes an angle of 45-¢/2 with horizontal.
=> Remember that angles are not indicated of Alpha.
In the above formulas, Alpha is the Critical Angle.
(10)
Prasanta naskar said:
1 decade ago
Active earth pressure is directly proportional to cot2 (45° + φ/2) or tan2 (45° - φ/2).
(1)
Harshdeep said:
8 years ago
Hers, cot^2(45 +B÷2 ) or by converting cot into tan^2 (90 -45 - B÷2) = tan^2 (45 - B÷2).
Zatak said:
10 years ago
Active earth pressure = ka*y*h where ka = (1-sinφ)/(1+sinφ) = tan2(45° - φ/2)
Akhil said:
7 years ago
Active earth pressure = 1/(tan2 (45° + π/2)) = tan2 (45° + π/2)
ka = 1/ kp.
ka = 1/ kp.
(2)
Sudipta said:
7 years ago
ka=1/tan^2(45°+Φ/2).
=tan^2(45°+Φ/2).
=flow value.
=tan^2(45°+Φ/2).
=flow value.
Harsh Shah said:
3 years ago
What will be for passive earth pressure of soil? Please explain.
Romy mehra said:
8 years ago
The value. Tan^2 (45 +φ/2) is for passive earth pressure.
Manoj said:
4 years ago
According to me, Pa is proportional to cot^2(45+π/2).
Gopalakrishnan said:
8 years ago
@Tanupa. Passive earth pressure = Tan^2(45+ angle\2).
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