Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 2)
2.
The active earth pressure of a soil is proportional to (where φ is the angle of friction of the soil)
tan (45° - φ)
tan2 (45° + φ/2)
tan2 (45° - φ/2)
tan (45° + φ)
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
21 comments Page 2 of 3.

Mahesh said:   6 years ago
How to calculate the angle? Please, anyone, tell me.

Sanjay said:   8 years ago
tan2(45+π/2).
Where π=angle of friction.

Ravi said:   3 years ago
I think this term is also called flow value.
(1)

Tanupa said:   9 years ago
What is equation of passive earth pressure?

Yaseen said:   8 years ago
Right. Thanks for the given explanation.

Joseph Nigus said:   3 years ago
The correct answer is option B.
(1)

Paul said:   7 years ago
What will be for soil at rest?

Staffana aishwarya said:   7 years ago
Soil at rest K0 = 1 - sinΠ.

Abhishikta said:   9 years ago
Ka = 1/tan^2(45 + φ/2).

Avinash said:   8 years ago
Y and h are constants.


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