# Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

### Discussion :: Soil Mechanics and Foundation Engineering - Section 1 (Q.No.2)

2.

The active earth pressure of a soil is proportional to (where φ is the angle of friction of the soil)

 [A]. tan (45° - φ) [B]. tan2 (45° + φ/2) [C]. tan2 (45° - φ/2) [D]. tan (45° + φ)

Explanation:

No answer description available for this question.

 Prasanta Naskar said: (Nov 17, 2014) Active earth pressure is directly proportional to cot2 (45° + φ/2) or tan2 (45° - φ/2).

 Astik said: (Feb 26, 2015) What is this process?

 Zatak said: (Jul 17, 2015) Active earth pressure = ka*y*h where ka = (1-sinφ)/(1+sinφ) = tan2(45° - φ/2)

 Tanupa said: (Aug 29, 2016) What is equation of passive earth pressure?

 Gopalakrishnan said: (Oct 6, 2016) @Tanupa. Passive earth pressure = Tan^2(45+ angle\2).

 Abhishikta said: (Feb 24, 2017) Ka = 1/tan^2(45 + φ/2).

 Yaseen said: (Mar 23, 2017) Right. Thanks for the given explanation.

 Harshdeep said: (Mar 30, 2017) Hers, cot^2(45 +B÷2 ) or by converting cot into tan^2 (90 -45 - B÷2) = tan^2 (45 - B÷2).

 Avinash said: (Apr 15, 2017) Y and h are constants.

 Romy Mehra said: (Sep 15, 2017) The value. Tan^2 (45 +φ/2) is for passive earth pressure.

 Sanjay said: (Oct 21, 2017) tan2(45+π/2). Where π=angle of friction.

 Akhil said: (Dec 2, 2017) Active earth pressure = 1/(tan2 (45° + π/2)) = tan2 (45° + π/2) ka = 1/ kp.

 Sudipta said: (Feb 14, 2018) ka=1/tan^2(45°+Φ/2). =tan^2(45°+Φ/2). =flow value.

 Paul said: (Apr 25, 2018) What will be for soil at rest?

 Staffana Aishwarya said: (May 9, 2018) Soil at rest K0 = 1 - sinΠ.

 Mahesh said: (Mar 13, 2019) How to calculate the angle? Please, anyone, tell me.