Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

2. 

The active earth pressure of a soil is proportional to (where φ is the angle of friction of the soil)

[A]. tan (45° - φ)
[B]. tan2 (45° + φ/2)
[C]. tan2 (45° - φ/2)
[D]. tan (45° + φ)

Answer: Option C

Explanation:

No answer description available for this question.

Prasanta Naskar said: (Nov 17, 2014)  
Active earth pressure is directly proportional to cot2 (45° + φ/2) or tan2 (45° - φ/2).

Astik said: (Feb 26, 2015)  
What is this process?

Zatak said: (Jul 17, 2015)  
Active earth pressure = ka*y*h where ka = (1-sinφ)/(1+sinφ) = tan2(45° - φ/2)

Tanupa said: (Aug 29, 2016)  
What is equation of passive earth pressure?

Gopalakrishnan said: (Oct 6, 2016)  
@Tanupa. Passive earth pressure = Tan^2(45+ angle\2).

Abhishikta said: (Feb 24, 2017)  
Ka = 1/tan^2(45 + φ/2).

Yaseen said: (Mar 23, 2017)  
Right. Thanks for the given explanation.

Harshdeep said: (Mar 30, 2017)  
Hers, cot^2(45 +B÷2 ) or by converting cot into tan^2 (90 -45 - B÷2) = tan^2 (45 - B÷2).

Avinash said: (Apr 15, 2017)  
Y and h are constants.

Romy Mehra said: (Sep 15, 2017)  
The value. Tan^2 (45 +φ/2) is for passive earth pressure.

Sanjay said: (Oct 21, 2017)  
tan2(45+π/2).
Where π=angle of friction.

Akhil said: (Dec 2, 2017)  
Active earth pressure = 1/(tan2 (45° + π/2)) = tan2 (45° + π/2)
ka = 1/ kp.

Sudipta said: (Feb 14, 2018)  
ka=1/tan^2(45°+Φ/2).
=tan^2(45°+Φ/2).
=flow value.

Paul said: (Apr 25, 2018)  
What will be for soil at rest?

Staffana Aishwarya said: (May 9, 2018)  
Soil at rest K0 = 1 - sinΠ.

Mahesh said: (Mar 13, 2019)  
How to calculate the angle? Please, anyone, tell me.

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