Civil Engineering  Soil Mechanics and Foundation Engineering  Discussion
Discussion :: Soil Mechanics and Foundation Engineering  Section 1 (Q.No.2)
2. 
The active earth pressure of a soil is proportional to (where φ is the angle of friction of the soil) 
[A]. 
tan (45°  φ)  [B]. 
tan^{2} (45° + φ/2)  [C]. 
tan^{2} (45°  φ/2)  [D]. 
tan (45° + φ) 
Answer: Option C
Explanation:
No answer description available for this question.

Prasanta Naskar said:
(Nov 17, 2014)


Active earth pressure is directly proportional to cot2 (45° + φ/2) or tan2 (45°  φ/2). 
Astik said:
(Feb 26, 2015)


What is this process? 
Zatak said:
(Jul 17, 2015)


Active earth pressure = ka*y*h where ka = (1sinφ)/(1+sinφ) = tan2(45°  φ/2) 
Tanupa said:
(Aug 29, 2016)


What is equation of passive earth pressure? 
Gopalakrishnan said:
(Oct 6, 2016)


@Tanupa. Passive earth pressure = Tan^2(45+ angle\2). 
Abhishikta said:
(Feb 24, 2017)


Ka = 1/tan^2(45 + φ/2). 
Yaseen said:
(Mar 23, 2017)


Right. Thanks for the given explanation. 
Harshdeep said:
(Mar 30, 2017)


Hers, cot^2(45 +B÷2 ) or by converting cot into tan^2 (90 45  B÷2) = tan^2 (45  B÷2). 
Avinash said:
(Apr 15, 2017)


Y and h are constants. 
Romy Mehra said:
(Sep 15, 2017)


The value. Tan^2 (45 +φ/2) is for passive earth pressure. 
Sanjay said:
(Oct 21, 2017)


tan2(45+π/2).
Where π=angle of friction. 
Akhil said:
(Dec 2, 2017)


Active earth pressure = 1/(tan2 (45° + π/2)) = tan2 (45° + π/2)
ka = 1/ kp. 
Sudipta said:
(Feb 14, 2018)


ka=1/tan^2(45°+Φ/2).
=tan^2(45°+Φ/2).
=flow value. 
Paul said:
(Apr 25, 2018)


What will be for soil at rest? 
Staffana Aishwarya said:
(May 9, 2018)


Soil at rest K0 = 1  sinΠ. 
Mahesh said:
(Mar 13, 2019)


How to calculate the angle? Please, anyone, tell me. 