Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 45)
45.
A coarse-grained soil has a voids ratio 0.75, and specific gravity as 2.75. The critical gradient at which quick sand condition occurs, is
Discussion:
21 comments Page 2 of 3.
Sahana said:
5 years ago
Compute the critical hydraulic gradient for a course gravel with k=6cm/sec gs=2.65 e=0.35.
(2)
Abiral said:
9 years ago
We know that,
The critical hydraulic gradient = (G-1)/(1+e) = (2.75-1)/(1+0.75) = 1.
The critical hydraulic gradient = (G-1)/(1+e) = (2.75-1)/(1+0.75) = 1.
Pratyush said:
9 years ago
@Laxman.
Yes, you are right critical hydraulic gradient is always 1.
Yes, you are right critical hydraulic gradient is always 1.
JayRam said:
10 years ago
Critical hydraulic gradient (i) = G-1/1+e.
i = 2.5-1/1+0.75.
= 1.0.
i = 2.5-1/1+0.75.
= 1.0.
DIPANJAN BHADRA said:
4 years ago
Critical gradient (ID) = (G-1)/(1+e),
= (2.75-1)/(1+0.75),
= 1.
= (2.75-1)/(1+0.75),
= 1.
(3)
Bhakti said:
1 decade ago
Quick sand condition occurs in fine sand and silt.
Ashok yadav said:
4 years ago
Ic = G-1/1+e,
= (2.75-1)/(1+0.75),
= 1.
= (2.75-1)/(1+0.75),
= 1.
(3)
Vijaykumar said:
6 years ago
ic = (G-1)/(1+e).
ic = (2.75-1)/(1+0.75) = 1.
ic = (2.75-1)/(1+0.75) = 1.
(1)
Abhinandan kumar said:
8 years ago
ic=g-1/1+e then head loss =ic*thickness.
Mayur said:
6 years ago
@ Khan,
i=(G-1)*((1-n).
i=(G-1)*((1-n).
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