Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 3 (Q.No. 24)
24.
The stem of a cantilever retaining wall which retains earth level with top is 6 m. If the angle of repose and weight of the soil per cubic metre are 30° and 2000 kg respectively, the effective width of the stem at the bottom, is
Discussion:
8 comments Page 1 of 1.
Lokesh said:
3 years ago
@Akhil.
How q and y values are obtained? Please explain.
How q and y values are obtained? Please explain.
Akhil said:
5 years ago
Min depth of foundation=q/y(1-sinθ/1+sinθ)^2.
Q = 180 y = 18.
So D min = 1.11.
Total height = 6+1.11 =7.11.
Base width = 0.75 * 7.11 = 5.3325 = 53.32.
Q = 180 y = 18.
So D min = 1.11.
Total height = 6+1.11 =7.11.
Base width = 0.75 * 7.11 = 5.3325 = 53.32.
(2)
Wanda said:
6 years ago
Depth of base =.7 * H = .42.
Total height = 6.42.
Now stem t = H/12 = 6.42/12 = 53.5.
Total height = 6.42.
Now stem t = H/12 = 6.42/12 = 53.5.
(8)
ARNAB MAITI said:
7 years ago
Explain the answer clearly.
Parthiban S said:
8 years ago
From the above mentioned we all get answer as, 0.55m (depth of foundation).then width of btm slab=thickness of bottom stem web..now width of bottom slab=H/12.i.e, H=height of stem above earth + depth of foundation I.e..,6+.55=6.55..now using the formula H/12 6.55/12=5.458 the nearest and will come.
Parthiban S said:
8 years ago
q/un.wt of soil(1-sin@/1+sin@)^2.
100/20(1-sin30/1+sin30)^2=54.625.
This is the nearest answer for what you have given as options.
100/20(1-sin30/1+sin30)^2=54.625.
This is the nearest answer for what you have given as options.
Laura said:
9 years ago
How the answer becomes 53.5?
Explain.
Explain.
Raj said:
9 years ago
How the answer becomes 53.5?
Please explain it.
Please explain it.
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