Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 5 (Q.No. 7)
7.
An intermediate T-beam reinforced with two layers of tensile steel with clear cover 13 cm encasted with the floor of a hall 12 metres by 7 metres, is spaced at 3 metres from adjoining beams and if the width of the beam is 20 cm, the breadth of the flange is
Discussion:
14 comments Page 1 of 2.
Pranab said:
9 years ago
Breadth of T-beam is:
1) 1/3 of eff span.
2) center to center distance of beam.
3) 12x depth of flange + width of the beam.
Which ever is less
Answer is;
As per 1) (300-20+13)/3 = 97.66 cm.
As per 2) 300 cm.
As per 3) 12x13+20 = 176 cm.
According to the conditions less is 97.66 cm.
1) 1/3 of eff span.
2) center to center distance of beam.
3) 12x depth of flange + width of the beam.
Which ever is less
Answer is;
As per 1) (300-20+13)/3 = 97.66 cm.
As per 2) 300 cm.
As per 3) 12x13+20 = 176 cm.
According to the conditions less is 97.66 cm.
(1)
Prasanna Gosavi said:
4 years ago
The breadth of T-beam is:
1) 1/3 of effective span.
2) center to centre distance of the beam.
3) 12 x depth of flange + width of the beam.
Whichever is minimum;
1) 1200/3 = 400 cm,
2) 300 cm,
3) 12 x 13 + 20 = 176 cm.
So, the correct answer for this question is 176 cm.
1) 1/3 of effective span.
2) center to centre distance of the beam.
3) 12 x depth of flange + width of the beam.
Whichever is minimum;
1) 1200/3 = 400 cm,
2) 300 cm,
3) 12 x 13 + 20 = 176 cm.
So, the correct answer for this question is 176 cm.
(2)
Jaya Tamrakar said:
5 years ago
The breadth of T-beam is:
1) 1/3 of eff span.
2) center to centre distance of the beam.
3) 12x depth of flange + width of the beam.
Which ever is less
1) 1200/3 = 400 cm,
2) 300 cm,
3) 12x13+20 = 176 cm.
The ans.is 176 cm.
1) 1/3 of eff span.
2) center to centre distance of the beam.
3) 12x depth of flange + width of the beam.
Which ever is less
1) 1200/3 = 400 cm,
2) 300 cm,
3) 12x13+20 = 176 cm.
The ans.is 176 cm.
(1)
Yogi said:
6 years ago
The breadth of T-beam is:
1) 1/3 of eff span.
2) centre to centre distance of the beam.
3) 12x depth of flange + width of the beam.
Which ever is less:
Answer is;
1) 1200/3 = 400 cm.
2) 300 cm.
3) 12x13+20 = 176 cm ans.
1) 1/3 of eff span.
2) centre to centre distance of the beam.
3) 12x depth of flange + width of the beam.
Which ever is less:
Answer is;
1) 1200/3 = 400 cm.
2) 300 cm.
3) 12x13+20 = 176 cm ans.
(1)
Snehal wankhede said:
9 years ago
For Isolated T beams,
Bf = bw + L/ (L/b + 4) = 200 + 7000/ (7000/200 + 4) = 379.5 mm < b (200 mm) as per IS code.
So the only option is C = 176 M.
I didn't get it either but it is as per IS CODE 456 : 2000.
Bf = bw + L/ (L/b + 4) = 200 + 7000/ (7000/200 + 4) = 379.5 mm < b (200 mm) as per IS code.
So the only option is C = 176 M.
I didn't get it either but it is as per IS CODE 456 : 2000.
(2)
Snehal wankhede said:
9 years ago
Breadth of flange (bf) > width of beam(bw). So answer is not option C.
Er charu said:
9 years ago
I want Explanation. Please explain this.
Akiyo said:
9 years ago
Please solve and explain clearly.
(1)
Abhishek said:
7 years ago
It should be an isolated T beam.
Astha Bhandari said:
7 years ago
Can anyone explain it clearly?
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