Civil Engineering - Railways - Discussion
Discussion Forum : Railways - Section 1 (Q.No. 2)
2.
If absolute levels of rails at the consecutive axles A, B, and C separated by 1.8 metres are 100.505 m, 100.530 m, and 100.525 m respectively, the unevenness of rails, is
Discussion:
31 comments Page 3 of 4.
Vikas mahto said:
7 years ago
Please give solution clearly.
Amu bokato said:
6 years ago
I am not getting this. Please, anyone explain it in clearly.
Sattu said:
6 years ago
Take the mean of all values.
(100.505+ 100.525 + 100.530)/3 - - 100.520.
Unevenness -- 100.520/1.8.
(100.505+ 100.525 + 100.530)/3 - - 100.520.
Unevenness -- 100.520/1.8.
(1)
Manju said:
6 years ago
Please anyone explain in detail.
Palak kesharwani said:
5 years ago
Please give detail description.
(1)
Asif wazir said:
5 years ago
Tan-1 (.025/1.8)-tan-1(.005/1.8) = .063m.
Vivek shukla said:
5 years ago
(100.505 + 100.525 + 100.530)/3 = 100.520.
Unevenness = { (100.505 - 100.520)+ (100.530 - 100.520) + (100.525 - 100.520) } ÷ 1.8 = 0.065.
Unevenness = { (100.505 - 100.520)+ (100.530 - 100.520) + (100.525 - 100.520) } ÷ 1.8 = 0.065.
(5)
Aamir Ashraf said:
4 years ago
Unevenness - The longitudinal unevenness of rails is measured as a deviation in the vertical plane (depression or rise) of the middle axle of the measuring bogie with reference to the average position of the two outer axles.
The outer axles are spaced 3.6 metres apart and unevenness is recorded to a scale of 1:1 on a base of 3.6 M for left and right rail separately.
The outer axles are spaced 3.6 metres apart and unevenness is recorded to a scale of 1:1 on a base of 3.6 M for left and right rail separately.
Naseer said:
4 years ago
Anyone, Please solve it in detail.
(1)
Tariq Marwat said:
3 years ago
Please explain me the correct answer.
(1)
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