Civil Engineering - Railways - Discussion
Discussion Forum : Railways - Section 1 (Q.No. 2)
2.
If absolute levels of rails at the consecutive axles A, B, and C separated by 1.8 metres are 100.505 m, 100.530 m, and 100.525 m respectively, the unevenness of rails, is
Discussion:
31 comments Page 2 of 4.
Mohan kumar said:
9 years ago
Anyone solve this question with clear solution?
Rajesh Shivapurkar said:
9 years ago
Explain the answer.
Adithya S said:
9 years ago
Can anyone explain the answer?
Ravi said:
9 years ago
Please explain the answer.
Rajesh Badugu said:
9 years ago
Find mean of all, you ll get 100.520
Unevenness = |100.505 - 100.520| + |100.530 - 100.520| + |100.525 - 100.520| divided by 1.8 = 0.063888.
Unevenness = |100.505 - 100.520| + |100.530 - 100.520| + |100.525 - 100.520| divided by 1.8 = 0.063888.
Pooja said:
9 years ago
Please solve this question with an explanation.
Prakash said:
9 years ago
100.505,100.530,100.525 level.
.505, .530, .525.
0.005 + 0.030 + 0.025 = 0.060 m.
.505, .530, .525.
0.005 + 0.030 + 0.025 = 0.060 m.
Chandrika said:
8 years ago
But if we are calculating the mean we are getting zero how are we supposed to solve? Can anyone explain me?
RABI said:
7 years ago
Please explain in detail.
Sandeep Ahirwar said:
7 years ago
Please explain the answer clearly.
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