Civil Engineering - Railways - Discussion
Discussion Forum : Railways - Section 1 (Q.No. 2)
2.
If absolute levels of rails at the consecutive axles A, B, and C separated by 1.8 metres are 100.505 m, 100.530 m, and 100.525 m respectively, the unevenness of rails, is
Discussion:
31 comments Page 1 of 4.
Hardinge said:
3 years ago
@All.
U= (a+b)/2 - d.
Where a and b are the absolute levels of the 2 end axles and d is the absolute level of the middle axle.
Now the problem here is that the question here has given incorrect data. The book that this question has been copied from had actually given the middle value as 100.580 which has been misprinted as 100.530 here.
If you put the middle value as 100.580 in the above formula you will get the answer exactly.
Take a=100.505.
b=100.525.
d=100.580.
Now solve you will get 0.065 m as the answer exactly.
U= (a+b)/2 - d.
Where a and b are the absolute levels of the 2 end axles and d is the absolute level of the middle axle.
Now the problem here is that the question here has given incorrect data. The book that this question has been copied from had actually given the middle value as 100.580 which has been misprinted as 100.530 here.
If you put the middle value as 100.580 in the above formula you will get the answer exactly.
Take a=100.505.
b=100.525.
d=100.580.
Now solve you will get 0.065 m as the answer exactly.
(8)
Aamir Ashraf said:
4 years ago
Unevenness - The longitudinal unevenness of rails is measured as a deviation in the vertical plane (depression or rise) of the middle axle of the measuring bogie with reference to the average position of the two outer axles.
The outer axles are spaced 3.6 metres apart and unevenness is recorded to a scale of 1:1 on a base of 3.6 M for left and right rail separately.
The outer axles are spaced 3.6 metres apart and unevenness is recorded to a scale of 1:1 on a base of 3.6 M for left and right rail separately.
Rajesh Badugu said:
9 years ago
Find mean of all, you ll get 100.520
Unevenness = |100.505 - 100.520| + |100.530 - 100.520| + |100.525 - 100.520| divided by 1.8 = 0.063888.
Unevenness = |100.505 - 100.520| + |100.530 - 100.520| + |100.525 - 100.520| divided by 1.8 = 0.063888.
Vivek shukla said:
5 years ago
(100.505 + 100.525 + 100.530)/3 = 100.520.
Unevenness = { (100.505 - 100.520)+ (100.530 - 100.520) + (100.525 - 100.520) } ÷ 1.8 = 0.065.
Unevenness = { (100.505 - 100.520)+ (100.530 - 100.520) + (100.525 - 100.520) } ÷ 1.8 = 0.065.
(5)
Chandrika said:
8 years ago
But if we are calculating the mean we are getting zero how are we supposed to solve? Can anyone explain me?
Sattu said:
6 years ago
Take the mean of all values.
(100.505+ 100.525 + 100.530)/3 - - 100.520.
Unevenness -- 100.520/1.8.
(100.505+ 100.525 + 100.530)/3 - - 100.520.
Unevenness -- 100.520/1.8.
(1)
Prakash said:
9 years ago
100.505,100.530,100.525 level.
.505, .530, .525.
0.005 + 0.030 + 0.025 = 0.060 m.
.505, .530, .525.
0.005 + 0.030 + 0.025 = 0.060 m.
Amu bokato said:
6 years ago
I am not getting this. Please, anyone explain it in clearly.
Pooja said:
9 years ago
Please solve this question with an explanation.
Mohan kumar said:
9 years ago
Anyone solve this question with clear solution?
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