Civil Engineering - Irrigation - Discussion
Discussion Forum : Irrigation - Section 2 (Q.No. 10)
10.
If the irrigation efficiency is 80%, conveyance losses are 20% and the actual depth of watering is 16 cm, the depth of water required at the canal outlet, is
Discussion:
33 comments Page 2 of 4.
Bhawesh said:
5 years ago
20/(0.8*0.8)=25.
80% Conveyance efficiency.
80% Irrigation Efficiency.
80% Conveyance efficiency.
80% Irrigation Efficiency.
RAHUL said:
1 decade ago
Hence, after losses = X-X/5 = 4X/5.
= 4X/5*80/100 = 16.
X = 25.
= 4X/5*80/100 = 16.
X = 25.
Ghulam mujatab said:
5 years ago
16*.80= 12.8 efficiency,
16*.20= 3.2 loss,
16+(12.8-3.2)=25.6~25.
16*.20= 3.2 loss,
16+(12.8-3.2)=25.6~25.
(1)
Jeff said:
8 years ago
@Anil.
What if efficiency is 80% and conveyance losses is 12%?
What if efficiency is 80% and conveyance losses is 12%?
Ahmad Mujtaba said:
4 years ago
(100-Efficiency) / (100-Loss) = 0.25.
0.25 x 100.
= 25cm.
0.25 x 100.
= 25cm.
(7)
Nareshsingh said:
6 years ago
X* (80/100)-x * (80/100 * 20/100) = 16.
So x = 25.
So x = 25.
Samim said:
5 years ago
16/(0.8 *0.8) = 25.
80% = 0.8,
100 - 20 % = 0.8.
80% = 0.8,
100 - 20 % = 0.8.
Akash vardhan said:
7 years ago
Thanks all of you for explaining the answer.
RAJAT said:
8 years ago
Yes, now clearly understood thank you @Rosh.
Mayur said:
7 years ago
Not understood. Please explain me clearly.
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