Civil Engineering - Hydraulics - Discussion

Discussion Forum : Hydraulics - Section 2 (Q.No. 4)
4.
A rectangular channel 6 m wide and 3 m deep and having a bed slope as 1 in 2000 is running full. If Chezy's constant C = 54.8, pick up the correct specification of the channel from the following :
hydraulic mean depth = 1.5 m
Velocity of flow = 1.5 m/sec
Rate of flow = 27 m3/sec
All the above.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Swathi said:   2 months ago
R = b*d/b+2*d.
V = c*√r*s.
Q = a*v.

Pkota said:   2 years ago
V = C(mi)^0.5.
m - hyd mean depth A/P.
i-slope.
Q = AV.

Gadadhar said:   3 years ago
Hydraulic radius = 1.5.
Hydraulic mean depth = (area/top width),
= 18/6,
= 3.

Dheeraj kataria said:   3 years ago
@Deep the way you find velocity is wrong.

The correct way to find velocity is v=c (mi) ^0.5.

And.

Rest of the all calculations are correct.

UDAYNARAYAN said:   3 years ago
Rec-perimeter (weted) = 3+6+3 = 12m.

Shreedevi said:   4 years ago
Thank you for explaining.

Manjunath said:   4 years ago
Hydraulic depth = area/top width.
H D= 6 * 3/6 = 3m.
But in answer is given hydraulic mean depth is 1.5m this one is hydraulic mean radius.

Meron said:   4 years ago
It is an opened channel so there is no one side length.
2b+L=p.

Dar Aashu said:   5 years ago
Wetted perimeter =2*h+b,
=2*3+6
=6+6.
P=12.

Abdul Bari said:   5 years ago
Perimeter of rectangular notch = b+2h.
So, 6+(2*3)=12m.


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