Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 2 (Q.No. 4)
4.
A rectangular channel 6 m wide and 3 m deep and having a bed slope as 1 in 2000 is running full. If Chezy's constant C = 54.8, pick up the correct specification of the channel from the following :
Discussion:
15 comments Page 2 of 2.
Rahul kumar said:
8 years ago
Perimeter of rectangular = b + 2h.
So, 6 + 2 * 3 = 12.
So, 6 + 2 * 3 = 12.
Solomon said:
8 years ago
How can the perimeter be 12?
Sudhansu bhagat said:
9 years ago
V = C * square root of RS.
V = 54.8 * square root of (1.5 * 0.0005).
= 1.5 m/s.
V = 54.8 * square root of (1.5 * 0.0005).
= 1.5 m/s.
Ahire ramkisan said:
1 decade ago
Let are be the hydrolic depth=1.5m.
S be the bed slope = 0.0005.
C is the chezys constant = 54.8.
Now we know that:
Velocity = 54.8*1.22*0.0005 = 1.5m/sec.
Discharge Q = a*v = 6*4*1.5 = 27.
S be the bed slope = 0.0005.
C is the chezys constant = 54.8.
Now we know that:
Velocity = 54.8*1.22*0.0005 = 1.5m/sec.
Discharge Q = a*v = 6*4*1.5 = 27.
(1)
Deep said:
1 decade ago
Hydraulic mean depth = area/perimeter.
R=a/p
R=18/12.
R=1.5.
V=c*r*s.
V=54.8*1.5*.0004.
V=1.50075m/s.
Q=a.v.
Q=18*1.5.
Q=27m3/s.
R=a/p
R=18/12.
R=1.5.
V=c*r*s.
V=54.8*1.5*.0004.
V=1.50075m/s.
Q=a.v.
Q=18*1.5.
Q=27m3/s.
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