Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 16)
16.
The ratio of maximum velocity to average velocity of viscous fluid through a circular pipe is
Discussion:
27 comments Page 1 of 3.
BugtiMehdi said:
2 years ago
For a fully developed laminar viscous flow through a circular pipe, the maximum velocity is equal to twice the average velocity.
Vavrg = 2 × Vmax.
Vavrg/Vmax = 2.
Vavrg = 2 × Vmax.
Vavrg/Vmax = 2.
(1)
Mesbah Ullah said:
4 years ago
The question is not clear where it is laminar or turbulant flow for oil in case of laminar it is 2 see Hagen–Poiseuille equation.
For some cases, it may 0.5. One thing must be clear that avg velocity is half of the max velocity and max velocity always exist at the centre of pipe.
For some cases, it may 0.5. One thing must be clear that avg velocity is half of the max velocity and max velocity always exist at the centre of pipe.
(1)
Muhammad Bilal said:
4 years ago
v/umax = 0.5.
Supreeth said:
4 years ago
Uavg= (umax)/2 so ratio will be 2.
Lavanyakondeti said:
4 years ago
Why answer is 2? Can you explain this answer?
Shravan said:
5 years ago
V(max) = 2V(avg.)
So, Vmax/Vavg.= 2.
So, Vmax/Vavg.= 2.
Parsolian said:
5 years ago
Umax/U=[1+1.43F^.5].
Which is;
Turbulent = 1.2-1.25.
Laminare = 2.
b/w plates = 1.5.
Which is;
Turbulent = 1.2-1.25.
Laminare = 2.
b/w plates = 1.5.
(1)
Harshit said:
6 years ago
Vmax/Vavg = 2 for laminar circular pipe flow.
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Vmax/Vavg = 3/2 for laminar fixed plate flow.
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Vmax/Vavg = 3/2 for laminar fixed plate flow.
(3)
Chandan Rakha said:
7 years ago
@Adie.
No, it's for plates 1.25.
No, it's for plates 1.25.
Adie said:
7 years ago
The answer is 3/2 or 1.25 for circular pipes.
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