Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 16)
16.
The ratio of maximum velocity to average velocity of viscous fluid through a circular pipe is
Discussion:
27 comments Page 1 of 3.
Harshit said:
6 years ago
Vmax/Vavg = 2 for laminar circular pipe flow.
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Vmax/Vavg = 3/2 for laminar fixed plate flow.
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Vmax/Vavg = 3/2 for laminar fixed plate flow.
(3)
Venkatesh naidu said:
8 years ago
In laminar flow, for pipes max.velocity= 2*avg.velocity.
For parallel plates max.velocity=1.50*avg.velocity.
For parallel plates max.velocity=1.50*avg.velocity.
(1)
BugtiMehdi said:
2 years ago
For a fully developed laminar viscous flow through a circular pipe, the maximum velocity is equal to twice the average velocity.
Vavrg = 2 × Vmax.
Vavrg/Vmax = 2.
Vavrg = 2 × Vmax.
Vavrg/Vmax = 2.
(1)
Mesbah Ullah said:
4 years ago
The question is not clear where it is laminar or turbulant flow for oil in case of laminar it is 2 see Hagen–Poiseuille equation.
For some cases, it may 0.5. One thing must be clear that avg velocity is half of the max velocity and max velocity always exist at the centre of pipe.
For some cases, it may 0.5. One thing must be clear that avg velocity is half of the max velocity and max velocity always exist at the centre of pipe.
(1)
Parsolian said:
5 years ago
Umax/U=[1+1.43F^.5].
Which is;
Turbulent = 1.2-1.25.
Laminare = 2.
b/w plates = 1.5.
Which is;
Turbulent = 1.2-1.25.
Laminare = 2.
b/w plates = 1.5.
(1)
Bhanu said:
7 years ago
Max.velocity= - 1 ÷ 4u (dp ÷ dx)*r^2
And avg. Velocity = -1 ÷8u (dp ÷ dx)*-r^2, so that the ratio will be = 2.
And avg. Velocity = -1 ÷8u (dp ÷ dx)*-r^2, so that the ratio will be = 2.
Anil said:
9 years ago
How the answer is 2?
Poobathy said:
9 years ago
How this answer?
Muhammad Bilal said:
4 years ago
v/umax = 0.5.
Supreeth said:
4 years ago
Uavg= (umax)/2 so ratio will be 2.
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