Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 16)
16.
The ratio of maximum velocity to average velocity of viscous fluid through a circular pipe is
Discussion:
27 comments Page 2 of 3.
Bhanu said:
7 years ago
Max.velocity= - 1 ÷ 4u (dp ÷ dx)*r^2
And avg. Velocity = -1 ÷8u (dp ÷ dx)*-r^2, so that the ratio will be = 2.
And avg. Velocity = -1 ÷8u (dp ÷ dx)*-r^2, so that the ratio will be = 2.
Lalitha said:
7 years ago
Not getting the solution, Please explain clearly.
Parrro said:
8 years ago
Please, Explain the process.
Venkatesh naidu said:
8 years ago
In laminar flow, for pipes max.velocity= 2*avg.velocity.
For parallel plates max.velocity=1.50*avg.velocity.
For parallel plates max.velocity=1.50*avg.velocity.
(1)
Michelle Mencias said:
8 years ago
If you solve this question for the laminar case the maximum velocity will be 2*uavg, 2*uavg, this means chaotic system dissipate more energy due to viscous effect. And can be related to the natural phenomenon as big eddies that form in the fluid consumes energy in form of angular velocity or vorticity and get converted to smaller eddies and eventually die out dissipating energy to the environment.
Sahil Sanjeev Salvi said:
8 years ago
Max. Velocity = 2 Avg. Velocity --> For Pipe.
Max. Velocity = 1.5 Avg. Velocity --> For Plate.
Max. Velocity = 1.5 Avg. Velocity --> For Plate.
Mahesh Walde said:
8 years ago
Boss maximum velocity is 0.97 and avg velocity is 0.81 then how become its ratio 2?
Vinaykumar Vk said:
8 years ago
Vavg = 1/8myu.dp/dx.R^2.
Vmax= 1/4myu.dp/dx.R^2.
Vmax= 1/4myu.dp/dx.R^2.
Vinaykumar Vk said:
8 years ago
In laminar flow, the maximum velocity is 2 times the average velocity.
Sunitha h s said:
9 years ago
Please can you describe the answer?
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