Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 44)
44.
A body of dimensions 1.5 m x 1.0 m x 2 m weighs 3000 kg in water. Its specific gravity is
Discussion:
27 comments Page 1 of 3.
Shailendra kumar said:
9 years ago
It is exactly 1.0 not 1.1.
Sp gr. = density of object ÷ density of std fluid.
Therefore density of object is 3000/3 = 1000.
Hence sp gr = 1000 ÷ 1000 = 1.
Sp gr. = density of object ÷ density of std fluid.
Therefore density of object is 3000/3 = 1000.
Hence sp gr = 1000 ÷ 1000 = 1.
(1)
Madhu said:
9 years ago
Yes, It is 1. Agree @Shailendra.
Xyz said:
9 years ago
It is greater than 1.
Anil said:
9 years ago
Yes, I too agree @Shailendra.
Xyz said:
9 years ago
Weights in water means buoyant force acting on it.
Dinesh prasad sao said:
8 years ago
Water specific gravity is always 1.
Babar said:
8 years ago
How it is 1.1?
Amit sharma said:
8 years ago
Here, mass/volume is density =1000kg/m'3 specific density is 1000/981 = 1.1.
Makar said:
8 years ago
I agree @Amit.
Wazeer Baloch said:
8 years ago
Specific Gravity is not about to density to density. It's about sp weight to sp weight. Density is 1000unit but Sp Weight is 981.
Now,
1000/1000 = 1 answer is correct.
Now,
1000/1000 = 1 answer is correct.
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